Conditional Independence Watch

Jeffery
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Report Thread starter 8 years ago
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We know that B1 is conditionally independent of B2 (given event A) if P(B1|A n B2) = P(B1|A).

How would i show that (B1 n B2 | A) = P (B1 | A)P(B2 | A), and how then could i show that P(B2|A n B1) = P(B2|A)?!

Suppose that B1 and B2 are independent. Does it necessarily follow that they are conditionally independant? Is there a proof for this?

Cheers for any help you can give me i really don't get this
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JamesyB
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Don't wanna ruin the party, but getting people to do your degree coursework for you is kinda not supposed to happen.
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