# How to solve this differential equationWatch

#1
dy/dt = 3y + 1 y(0)=0

When I integrate, I get:

1/(9y²) = t + c

But then you can't put the 0's in to find a value for c. What do you do?
0
8 years ago
#2

+ constant.

Or equivalently

0
#3
(Original post by marcusmerehay)

Oh yeah!!! Duhhh. Lol I was differentiating.

Thanks :
0
8 years ago
#4
(Original post by claret_n_blue)
dy/dt = 3y + 1 y(0)=0

When I integrate, I get:

1/(9y²) = t + c

But then you can't put the 0's in to find a value for c. What do you do?
You haven't rearranged/integrated correctly. You should be integrating 1/(3y+1) w.r.t y, which will have ln in it.
0
X

new posts
Latest
My Feed

### Oops, nobody has postedin the last few hours.

Why not re-start the conversation?

see more

### See more of what you like onThe Student Room

You can personalise what you see on TSR. Tell us a little about yourself to get started.

### University open days

• Cranfield University
Cranfield Forensic MSc Programme Open Day Postgraduate
Thu, 25 Apr '19
• University of the Arts London
Open day: MA Footwear and MA Fashion Artefact Postgraduate
Thu, 25 Apr '19
• Cardiff Metropolitan University
Sat, 27 Apr '19

### Poll

Join the discussion

#### Have you registered to vote?

Yes! (146)
38.32%
No - but I will (21)
5.51%
No - I don't want to (28)
7.35%
No - I can't vote (<18, not in UK, etc) (186)
48.82%