The Student Room Group
Reply 1
play_the_world
A student made 1.10g of dipeptide H starting from 1.40g of glycine.
Calculate the percentage yield (%) obtained. Give your answer to 3 sig. figs.

Thanks loads to anyone who can help me; I've always had trouble with percentage yields.... :frown:


What is there here not to understand?!

Percentage yield = End Product / Starting Product x 100

1.1 / 1.4 x 100 = 78.6%

In this reaction...

2 x glycine --> dipeptide + H20

since the dipeptide is formed by a condensation reaction the remaining 21.4% is due to the water produced
Reply 2
Well I thought it would be more complicated than that, because the question is worth 4 marks. Thanks alot anyway.
Reply 3
Actually, I think what you're looking for is:

% yield = [actual yield (in grams) / predicted yield (in grams) ] x 100

To work out the predicted yield you'd have to do some moles calculations using the equation for the reaction ... which would probably be why it's worth 4 marks.