Formulaec Question

Tin (Sn) reacts with iodine (I) in an organic solvent to form a covalent compound, SnI_x. When 0.4650g of tin (an excess) was used all the iodine reacted. A mass 0.1230g of unreacted tin and 1.8020 of SnI_x were obtained. Find the value of x.

Thanks in advance...

OP

Anyone?

Pixelated

I use a table method. If you would like an explanation of how... let me know.

x = 4

Reply 3

random123

2

Well this isn't really the proper way to do it, but the quickest way to do it is to say that the atomic mass of tin and Iodine are pretty much the same, Sn is 118.71, I is 126.90447.

Ok so, with that in mind:

If 0.4650g of tin is used and 0.1230g is unreacted, then 0.342g does react.

So if 0.342g of your 1.802g of SnI_x is tin, then 1.46g (1.802 - 0.342) of it is iodine.

Then to find the ratio of tin to iodine: 0.342 ÷ 1.46 ≈ 2.

So x = 2

NB. This only works if the atomic masses are roughly equal, I can't be bothered to do it the proper way.

Reply 4

random123

2

Well this isn't really the proper way to do it, but the quickest way to do it is to say that the atomic mass of tin and Iodine are pretty much the same, Sn is 118.71, I is 126.90447.

Ok so, with that in mind:

If 0.4650g of tin is used and 0.1230g is unreacted, then 0.342g does react.

So if 0.342g of your 1.802g of SnI_x is tin, then 1.46g (1.802 - 0.342) of it is iodine.

Then to find the ratio of iodine to tin: 1.46 ÷ 0.342 ≈ 4.

So x = 4

NB. This only works if the atomic masses are roughly equal, I can't be bothered to do it the proper way.

[EDIT] Actually the proper way is steve's way, which includes the extra step of dividing by the atomic masses before finding the ratio.

Reply 5

supreme

4

Pixelated

Tin (Sn) reacts with iodine (I) in an organic solvent to form a covalent compound, SnI_x. When 0.4650g of tin (an excess) was used all the iodine reacted. A mass 0.1230g of unreacted tin and 1.8020 of SnI_x were obtained. Find the value of x.

Thanks in advance...

Mass of Sn = 0.4650 g - 0.1230 g = 0.3420 g

Mass of I_x = 1.8020 g - 0.3420 g = 1.46 g

Ratio of masses: Sn : I_x

0.3420 g / 0.3420 g = 1.46 g / 0.3420 g

1:4

NB: Strictly speaking you should find the number of moles, in this case it doesn't matter but as steve pointed out its a good method to use.

This is the correct answer as it seems sensible and I have the book which includes the answer (although it didn't show the working just final answer).

Reply 6

steve2005

17

supreme

Mass of Sn = 0.4650 g - 0.1230 g = 0.3420 g

Mass of I_x = 1.8020 g - 0.3420 g = 1.46 g

Ratio of masses: Sn : I_x

0.3420 g / 0.3420 g = 1.46 g / 0.3420 g

1:4

NB: It is unecessary to convert to number of moles. Also notice how grams cancel.

This is the correct answer as it seems sensible and I have the book which includes the answer (although it didn't show the working just final answer).

Correct solution but wrong working, I'm afraid. You have to divide by the atomic mass of each element. Then you find the ratio ...

Reply 7

random123

2

steve2005

Correct solution but wrong working, I'm afraid. You have to divide by the atomic mass of each element. Then you find the ratio ...

Like I said in my post, yes to get it exact you have to do that, but as the atomic masses are roughly the same it doesn't matter.

Reply 8

Christophicus

18

steve2005

Correct solution but wrong working, I'm afraid. You have to divide by the atomic mass of each element. Then you find the ratio ...

It doesn't matter too much because the atomic masses of both elements are fairly similar anyway. :wink:

Reply 9

supreme

4

Yeah sorry, had a crazy moment....lack of sleep does do that :smile:

Lol widowmaker

Reply 10

carol05

Widowmaker

It doesn't matter too much because the atomic masses of both elements are fairly similar anyway. :wink:

It does matter: the method needs to be correct. The correct value for the wrong reason is not the way to go.

Formulaec Question

Related discussions

Articles for you