# OCR Mechanics 2 - circular motionWatch

Thread starter 7 years ago
#1
Hi all -

I'm stuck on a problem with circular motion.

Basically, particle A is rotating around a fixed point and is attached to particle B using a string which passes through the fixed point. Particle B hangs vertically below the fixed point in equilibrium.

Particle A has mass 0.3kg and Particle B has mass 0.7kg.

The distance from particle A to the fixed point is 0.3m

How would I go about finding the tension in the string? Is it not just 0.7g-0.4g = 0.3g?

cheers
wib
0
quote
7 years ago
#2
(Original post by wibletg)
Hi all -

I'm stuck on a problem with circular motion.

Basically, particle A is rotating around a fixed point and is attached to particle B using a string which passes through the fixed point. Particle B hangs vertically below the fixed point in equilibrium.

Particle A has mass 0.3kg and Particle B has mass 0.7kg.

The distance from particle A to the fixed point is 0.3m

How would I go about finding the tension in the string? Is it not just 0.7g-0.4g = 0.3g?

cheers
wib
Particle B is in equilibrium, so just resolve vertically at B, and you have the tension straight away.
quote
Thread starter 7 years ago
#3
(Original post by ghostwalker)
Particle B is in equilibrium, so just resolve vertically at B, and you have the tension straight away.
Ah, so tension is 0.7g. Cheers
0
quote
7 years ago
#4
(Original post by wibletg)
Ah, so tension is 0.7g. Cheers
quote
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