Is this right? (integration) Watch

Chemhistorian
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#1
Report Thread starter 7 years ago
#1
 \int \frac{1}{(2t+1)^2} \ dt

Let  u = 2t+1 \Rightarrow \frac{du}{dt} = 2

 \Rightarrow dt = \frac{du}{2} = \frac{1}{2}du

 \Rightarrow \int \frac{1}{2}u^{-2}du = \frac{1}{2} \int u^{-2}du

 = \frac{1}{2}(\frac{u^{-1}}{-1} + C) = \frac{1}{2}(-u^{-1} + C)

 = \frac{1}{2}(-\frac{1}{2t+1} + C)

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Piecewise
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#2
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Yep!
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Chemhistorian
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#3
Report Thread starter 7 years ago
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(Original post by Piecewise)
Yep!
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