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# OCR CORE 4 Intergration rep+ watch

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1. Hi,

Basically I can't do this question!

Intergrate cos^2 (1/2A) dx.

I presume this is similar to (Cos2A+1)/2 = Cos2A

So what do I do if I have, instead of 1A, 1/2A?
2. (Original post by Pheylan)
I have no idea how you did that....

If Cos2A= 2Cos^2A -1
and if I let 1/2x=A,

then Cos^2A= (Cos2A+1) /2

therefore Cos 1/2x= (CosX +1) /2??
3. (Original post by J DOT A)
Hi,

Basically I can't do this question!

Intergrate cos^2 (1/2A) dx.

I presume this is similar to (Cos2A+1)/2 = Cos2A

So what do I do if I have, instead of 1A, 1/2A?
Basically the same you usually would. The general idea is:

, except now on the LHS the A is (1/2)A and the RHS the angle is A

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Updated: March 14, 2011
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