[Q] Find the values of x for which the initial value problem
dy/dx = 2xy^2 , y(0)=1
has a stable numerical solution using the Euler Algorithm. What is the condition on h?
I know that if Jn>0 then the method is unstable, how should i go about proving this though, really not sure where to start.
I figured producing a euler algorithm over a range of x values from -1 to +1 to prove the stability would be suitable but this method has hit the rocks and i'm struggling.
I feel there is another way of showing the stable solution and finding the values of x.
Thanks in advance!!
Euler Algorithm watch
- Thread Starter
- 17-03-2011 19:36