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    [Q] Find the values of x for which the initial value problem

    dy/dx = 2xy^2 , y(0)=1

    has a stable numerical solution using the Euler Algorithm. What is the condition on h?


    I know that if Jn>0 then the method is unstable, how should i go about proving this though, really not sure where to start.
    I figured producing a euler algorithm over a range of x values from -1 to +1 to prove the stability would be suitable but this method has hit the rocks and i'm struggling.
    I feel there is another way of showing the stable solution and finding the values of x.


    Thanks in advance!!
 
 
 
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Updated: March 17, 2011
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