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    Need help with my rearranging please:

    y=3w-v/4x make x subject of formula

    w=t^2(2u-3v)/5s make v subject of formula

    Any help appreciated!
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    Make sure anything involving the thing you need to make the subject of is on one side first.

    In the first case you can rewrite it as \frac{v}{4x}=3w-y

    In the second case you can get (quite easily)  \frac{5sw}{t^2}=2u-3v and work from there.
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    in general...
    multiply out, move everything that includes the subject to one side, factorise, then divide through to get the subject by itself.
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    on the first one is it 3w-v all over 4x or 3w- (v/4x)
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    (Original post by didgeridoo12uk)
    in general...
    multiply out, move everything that includes the subject to one side, factorise, then divide through to get the subject by itself.
    ah..having little problem with these two questions,please could yo utell me answers so i can work out how you got them? thanks
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    (Original post by boba)
    on the first one is it 3w-v all over 4x or 3w- (v/4x)
    i can do it now thanks alot !x=v/12w-4y right?
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    Its just the second one now that i cant do,i get to the stage of 5sw/t^2=2u-3v then dont know how to get it aall make v
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    (Original post by cosmicalgebra)
    Its just the second one now that i cant do,i get to the stage of 5sw/t^2=2u-3v then dont know how to get it aall make v
    assuming what you have done so far is right because I haven't checked
    take the 2u over to the other side and divide by -3 ?
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    (Original post by boba)
    assuming what you have done so far is right because I haven't checked
    take the 2u over to the other side and divide by -3 ?
    how would that go?its all one fraction....
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    (Original post by cosmicalgebra)
    ah..having little problem with these two questions,please could yo utell me answers so i can work out how you got them? thanks
    basically do exactly what i said...

    w= \frac{t^2(2u-3v)}{5s}

    multiply it all out....
    5sw= 2t^2u-3t^2v

    put everything with v in on the same side...
    3t^2v= 2t^2u-5sw

    divide through to get v by itself...
    v= \frac{2t^2u-5sw}{3t^2}
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    (Original post by didgeridoo12uk)
    basically do exactly what i said...

    w= \frac{t^2(2u-3v)}{5s}

    multiply it all out....
    5sw= 2t^2u-3t^2v

    put everything with v in on the same side...
    3t^2v= 2t^2u-5sw

    divide through to get v by itself...
    v= \frac{2t^2u-5sw}{3t^2}
    Thanks alot,it never occured to expand...but i know now
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    (Original post by cosmicalgebra)
    Thanks alot,it never occured to expand...but i know now
    you can do it without expanding and some of the time it might be quicker. but generally i find it easier to just expand everything out and go from there especially when you can't see what to do
 
 
 
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