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    Hi, could someone please help,
    how would I split the following into partial fractions or even how would I divide the two quadratics?

    (x^2 + 6x + 7) / (x^2 + 5x + 6)

    Thank you
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    try writing x^2+6x+7 as x^2+5x+6 + {something else) then you have

    [x^2+5x+6+{something else}]/x^2+5x+6
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    (Original post by J00100)
    Hi, could someone please help,
    how would I split the following into partial fractions or even how would I divide the two quadratics?

    (x^2 + 6x + 7) / (x^2 + 5x + 6)

    Thank you
    Note that x^2+6x+7 = (x^2+5x+6) + (x+1) and then use the fact that \frac{a+b}{c} \equiv \frac{a}{c} + \frac{b}{c}. One of those fractions will simplify to 1.
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    (Original post by Farhan.Hanif93)
    Note that x^2+6x+7 = (x^2+5x+6) + (x+1) and then use the fact that \frac{a+b}{c} \equiv \frac{a}{c} + \frac{b}{c}. One of those fractions will simplify to 1.
    Thanks both of you!! Helped lots
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    There needs to be a sticky thread on how to solve partial equations. I see a million random partial fraction questions every day on here. Do your A-Level teachers teach everything in the syllabus EXCEPT partial fractions?
 
 
 
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