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    h3 +3hr2 -6v=0 can someone solve this cubic equation for me plzzzzz.....
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    h=0, v=0.
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    wat i didn't understand... can u plzz solve it...
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    I assume you mean:

    h^3 + 3hr^2 - 6v = 0

    If you subsitute h=0 and v=0, the equation is solved!
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    can you plzzzz spell correctly.
    (what, you and please by the way)
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    but i need to transpose h from this equation
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    are you there?
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    Transpose for h.
    V = (h/6)(3r^2 + h^2)
    Please help.......
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    Transpose for h.
    V = (h/6)(3r2 + h2)
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    h = -\frac{r^2}{(3 v + \sqrt{r^6 + 9 v^2})^{1/3}} + (3 v + \sqrt{r^6 + 9 v^2})^{1/3}

    is one solution. I must be bored.
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    hw did u work it out??
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    Who are you? What level of schooling are you at? Where did this question come from? What the hell does "transpose for h" mean?
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    hahaha... lol this is a question in my maths assignment for access to HE course..
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    transpose for h means make h subject of formula
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    Oh. I've never heard that phrase before. Looks like noobynoo already did it. I have no idea how though.
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    thats wat i ask him but he didn't reply..
 
 
 
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