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# Basic M1 velocity question watch

1. Neither the distance covered before the second brake or the time is given..

A car comes to a stop from a speed of 30 m/s in a distance of 830m. The driver brakes so as to produce a deceleration of 1/2 m/s^2 to begin with, and then brakes harder to produce a deceleration of 2/3 m/s^2. Find the speed of the car at the instant when the deceleration is increased, and the total time the car takes to stop..

Any hints on how to solve this?
2. You're given the total distance, so let the distance covered during the first deceleration be S, then during the second part he covers a distance of (830-S).

With the rest of the data you should be able to formulate two SUVAT expressions and solve (Hint: )
3. cheers
4. (Original post by marcusmerehay)
You're given the total distance, so let the distance covered during the first deceleration be S, then during the second part he covers a distance of (830-S).

With the rest of the data you should be able to formulate two SUVAT expressions and solve (Hint: )
This.

Also, you might have to look at the total change in velocity to produce another equation:

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