You are Here: Home

# Calculating the volume of hydrochloric acid watch

1. I'm working on this question: What volume of dilute hydrochloric acid that has the concentration 0.050 mol dm-3 is needed to react with a tablet containing 400 mg of calcium carbonate?

The first thing I did is wrote a balanced equation as follows (http://ca.answers.yahoo.com/question...0202727AAbwjZd):

CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l)

After that, I calculated the number of moles CaCO3 as follows:
#moles(CaCO3) = 0.4 g / 100 g mol-1 = 0.004 mol

Now, based on the stoichiometry of the reaction, the number of moles of HCl will be 2 X 0.004 mol = 0.008 mol

And, thus, based on this equation: concentration(mol dm-3) = number of moles (mol) / volume (dm3) we can caclulate the volume needed for HCl as follows:
0.050 mol dm-3 = 0.008 mol / volume (dm3)
volume = 0.008 mol / 0.050 mol dm-3 = 0.16 dm3

Is this correct?

Thanks.
2. (Original post by SWEngineer)
I'm working on this question: What volume of dilute hydrochloric acid that has the concentration 0.050 mol dm-3 is needed to react with a tablet containing 400 mg of calcium carbonate?

The first thing I did is wrote a balanced equation as follows (http://ca.answers.yahoo.com/question...0202727AAbwjZd):

CaCO3(s) + 2HCl(aq) --> CaCl2(aq) + CO2(g) + H2O(l)

After that, I calculated the [I]number of moles[I] CaCO3 has as follows:
#moles(CaCO3) = 0.4 g / 100 g mole-1 = 0.004 mol

Now, based on the stoichiometry of the reaction, the number of moles of HCl will be 2 X 0.004 mol = 0.008 mol

And, thus, based on this equation: concentration(mol dm-3) = number of moles (mol) / volume (dm3) we can caclulate the volume needed for HCl as follows:
0.050 mol dm-3 = 0.008 mol / volume (dm3)
volume = 0.008 mol / 0.050 mol dm-3 = 0.16 dm3

Is this correct?

Thanks.
yeah, i concur
3. Thanks @shengoc. Who else agrees with this solution? :-)
4. Yeah I agree

### Related university courses

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 19, 2011
Today on TSR

### Top unis in Clearing

Tons of places at all these high-ranking unis

### Best friend wants me to pick wedding dress

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE