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# C3 Trig Queation watch

1. a)Find the vale of arc sin 1/2 + arccos 1/2, giving your answer in radians in terms of
b) Given that angles A and B are defines as A=arcsin x and B= arccos x, -1x1 show that sin A=sinB
c) Hence deduce that arcsin x + arccos x=

Okay so I have part a and b down, I think;

a)arcsin (1/2) +arccos(1/2)=30+60=90

b) A=arcsin x
Thus x=sin A

B=arccos x
Thus x=cos B

therefore sin A=cos B
So, how do I proceed with part c?
2. (Original post by mintmocha)
a)Find the vale of arc sin 1/2 + arccos 1/2, giving your answer in radians in terms of
b) Given that angles A and B are defines as A=arcsin x and B= arccos x, -1x1
c) Hence deduce that arcsin x + arccos x=

So, how do I proceed with part c?

You don't seem to have written out part (b) fully, what you've posted there is not a question.

For part (c), maybe take the cosine of both sides first. Although I can't be sure what the question is looking for unless you post part (b) properly.
3. (Original post by mintmocha)
a)Find the vale of arc sin 1/2 + arccos 1/2, giving your answer in radians in terms of
b) Given that angles A and B are defines as A=arcsin x and B= arccos x, -1x1
c) Hence deduce that arcsin x + arccos x=

So, how do I proceed with part c?
a) Needs to be in terms of

Ok for c) you've said

x=sinA
x=cosA

How would you convert cos A into a form of sin A? Think: the angles add up to 90 degrees, as already stated in part c.
4. draw a right angled triangle and label the sides - think of as x in your equation

5. It is very similar to a question I just did:

Edexcel C3, Jan 2007, Question 8.
6. anyone else ?

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