the differential equation (d2y/dx2) + 6(dy/dx) = exp(3x)
when x = 0, y=0, dy/dx = 0
to solve can I just put the exp(3x) equal to zero because of the boundary condition and then solve from there, or is there something else I must do instead?
Turn on thread page Beta

danhirons
 Follow
 3 followers
 14 badges
 Send a private message to danhirons
 Thread Starter
Offline14ReputationRep: Follow
 1
 19032011 13:44

Revision help in partnership with Birmingham City University

Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 2
 19032011 13:49
(Original post by danhirons)
the differential equation (d2y/dx2) + 6(dy/dx) = exp(3x)
when x = 0, y=0, dy/dx = 0
to solve can I just put the exp(3x) equal to zero because of the boundary condition and then solve from there, or is there something else I must do instead?Last edited by Farhan.Hanif93; 19032011 at 13:50. 
danhirons
 Follow
 3 followers
 14 badges
 Send a private message to danhirons
 Thread Starter
Offline14ReputationRep: Follow
 3
 19032011 13:57
(Original post by Farhan.Hanif93)
Notice how this is a disguised first order DE. Use the substitution . The use the integrating factor method to get the CF and find the particular integral by plugging in a function of the form and solving for A.
Ahhh okay thank you, there's another question where the LHS is the same as in this question and RHS = 1 + 9x^2, do I do the same sort of thing in this question? 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 4
 19032011 13:59
(Original post by Farhan.Hanif93)
Notice how this is a disguised first order DE. Use the substitution . The use the integrating factor method to get the CF and find the particular integral by plugging in a function of the form and solving for A.
(Original post by danhirons)
the differential equation (d2y/dx2) + 6(dy/dx) = exp(3x)
when x = 0, y=0, dy/dx = 0
to solve can I just put the exp(3x) equal to zero because of the boundary condition and then solve from there, or is there something else I must do instead? 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 5
 19032011 13:59
(Original post by danhirons)
Ahhh okay thank you, there's another question where the LHS is the same as in this question and RHS = 1 + 9x^2, do I do the same sort of thing in this question? 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 6
 19032011 14:03
(Original post by TwilightKnight)
I've often found the problem with finding solutions like that is that you then try to tend to apply them in every situation, even if you can't. Unless it's an M5 Vector differential equation, I just generally try and keep the methods used to solve normal 1st ODE and 2nd ODEs separate. In FP2 they generally make it pretty clear which is which.
EDIT: I can't see why you'd use the substitution if it was clearly not going to work. It tends to be pretty obvious if an ODE of that form is a first order one in disguise. Obviously some substitution are harder to spot than others so if you can't spot it, you may as well try your 2nd order method.Last edited by Farhan.Hanif93; 19032011 at 14:09. 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 7
 19032011 14:08
(Original post by Farhan.Hanif93)
I disagree, I'm afraid. Solving most linear first order ODEs tends for be quite a bit less in terms of legwork than solving a second order one simply because there's less differentiation going on. So if a substitution simplifies things then you should almost definitely use it.
What I was trying to say, is that by this point in A Level Maths, you usually know a half dozen ways to solve certain equations. If you're doing the Further Mechanics units, then you probably know even more.
Sometimes, you'll forget that in order to do a substitution etc, you needed very specific criteria, and the methods begin to 'bleed' together. It's happened to me in the past, and I've tried to solve questions which just didn't lend themselves to that method and gone in circles for 20 minutes on a past paper before realising actually; do that.
All I was saying that was, in terms of making sure you do your best on the exam, sometimes it's easier to go in with a set way of doing something, rather than trying to improvise at the last minute with a method you might be unfamiliar with. 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 8
 19032011 14:16
(Original post by TwilightKnight)
I wasn't trying to say your method was wrong at all. In fact, it's brilliant. It makes it much quicker to solve.
What I was trying to say, is that by this point in A Level Maths, you usually know a half dozen ways to solve certain equations. If you're doing the Further Mechanics units, then you probably know even more.
Sometimes, you'll forget that in order to do a substitution etc, you needed very specific criteria, and the methods begin to 'bleed' together. It's happened to me in the past, and I've tried to solve questions which just didn't lend themselves to that method and gone in circles for 20 minutes on a past paper before realising actually; do that.
All I was saying that was, in terms of making sure you do your best on the exam, sometimes it's easier to go in with a set way of doing something, rather than trying to improvise at the last minute with a method you might be unfamiliar with.
I'm not too sure what these specific criteria are, though. There shouldn't be anything that is overly problematic when considering a substitution. It will either simplify things, or it won't. You don't need to worry about any conditions (AFAIK) so I'm not sure how it would become a problem.
Something important about maths, which is not really pushed enough in ALevel maths IMO, is that you should be able to string all your ideas together with confidence. So by combining the knowledge of substitution with the idea of linear 1st order ODEs, you can simplify a 2nd order ODE. In ALevel exams they seem to cripple this by either asking you to solve a question with just a single idea to it OR they will completely lead you through the problem by indicating what to do at each stage through breaking up the question into parts, which completely removes the opportunity for you to think of the idea yourself.
Exams tend to be time pressured and a method which can save time should really be considered if you're confident with it.
Besides this, the OP is actually at University doing a nonmaths degree so this idea of ALevel maths exams shouldn't really apply to him. 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 9
 19032011 14:26
(Original post by Farhan.Hanif93)
Fair enough.
I'm not too sure what these specific criteria are, though. There shouldn't be anything that is overly problematic when considering a substitution. It will either simplify things, or it won't. You don't need to worry about any conditions (AFAIK) so I'm not sure how it would become a problem.
Something important about maths, which is not really pushed enough in ALevel maths IMO, is that you should be able to string all your ideas together with confidence. So by combining the knowledge of substitution with the idea of linear 1st order ODEs, you can simplify a 2nd order ODE. In ALevel exams they seem to cripple this by either asking you to solve a question with just a single idea to it OR they will completely lead you through the problem by indicating what to do at each stage through breaking up the question into parts, which completely removes the opportunity for you to think of the idea yourself.
Exams tend to be time pressured and a method which can save time should really be considered if you're confident with it.
Besides this, the OP is actually at University doing a nonmaths degree so this idea of ALevel maths exams shouldn't really apply to him.
Anyway. I completely agree. When I did my C4 paper, I had already recently self taught bits of FP2 and FP3, and so I used a MacLaurin series to solve a binomial question, since it seemed the most logical way. I was able to find a perpendicular vector by using the cross product rather than making two line equations and doing about 20 lines of solving.
Unfortunately, in my case, I also tried to integrate a question directly rather than using parts because I remembered how to use Eulers relation on an integral of form e^x(trig function)[x] or using trig functions with powers more than 23, but the question didn't lend itself to it, and instead of getting a theta at the end, I got just a '1'. No marks. So I guess I'm an advocate of using whatever way works, but also have a cautionary tale to tell in order to make sure I don't do it in the future . 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 10
 19032011 14:35
(Original post by TwilightKnight)
Lol, didn't spot that.
Anyway. I completely agree. When I did my C4 paper, I had already recently self taught bits of FP2 and FP3, and so I used a MacLaurin series to solve a binomial question, since it seemed the most logical way. I was able to find a perpendicular vector by using the cross product rather than making two line equations and doing about 20 lines of solving.
Unfortunately, in my case, I also tried to integrate a question directly rather than using parts because I remembered how to use Eulers relation on an integral of form e^x(trig function)[x] or using trig functions with powers more than 23, but the question didn't lend itself to it, and instead of getting a theta at the end, I got just a '1'. No marks. So I guess I'm an advocate of using whatever way works, but also have a cautionary tale to tell in order to make sure I don't do it in the future . 
EEngWillow
 Follow
 6 followers
 11 badges
 Send a private message to EEngWillow
Offline11ReputationRep: Follow
 11
 19032011 14:57
I feel violated by my degree, I see an ODE and my first reaction is to use Laplace Transforms to solve it.

 Follow
 12
 19032011 16:18
(Original post by TwilightKnight)
Lol, didn't spot that.
Anyway. I completely agree. When I did my C4 paper, I had already recently self taught bits of FP2 and FP3, and so I used a MacLaurin series to solve a binomial question, since it seemed the most logical way. I was able to find a perpendicular vector by using the cross product rather than making two line equations and doing about 20 lines of solving.
Unfortunately, in my case, I also tried to integrate a question directly rather than using parts because I remembered how to use Eulers relation on an integral of form e^x(trig function)[x] or using trig functions with powers more than 23, but the question didn't lend itself to it, and instead of getting a theta at the end, I got just a '1'. No marks. So I guess I'm an advocate of using whatever way works, but also have a cautionary tale to tell in order to make sure I don't do it in the future . 
dknt
 Follow
 15 followers
 12 badges
 Send a private message to dknt
 Visit dknt's homepage!
Offline12ReputationRep: Follow
 13
 19032011 16:22
(Original post by anshul95)
I seen a couple of C4 papers were they were like if Maclaurin series was used they had to refer the answer to their "senior examiner". I remember I used the cross product for a C4 past paper question and the method wasn't on the mark scheme so I had to give myself zero for that question . 
 Follow
 14
 19032011 18:56
(Original post by dknt)
Really? According to my teacher, as long as you got the right answer and used a perfectly valid method you should still get the marks, as long as they didn't explicitly state "by using the dot product" or whatever. 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 15
 20032011 13:40
(Original post by anshul95)
well I was only practising so not much harm done, but I did ask my teachers the next day I got a mixed response.
90 times out of a 100, that wouldn't be a problem, exams are fairly standard these days, and most of the time, the markscheme is just like a checklist. However, with something like Maths, where you can often use methods outside of the syllabus for that paper, you really need someone who knows Maths like the back of their hand. I guess that's where the 'refer to coordinator' stuff comes from, but I'm willing to bet at least some of the time, notes like that just get ignored when the markers are tired and want to go to bed/ go out etc.
So, I'd say generally, use the method appropriate for the paper, but, if you're absolutely certain of the method you intend to use and you know for certain you will get the right answer quicker and more efficiently, go for that. Because if you're more familiar with that method, the chances are you aren't going to slip up with it, which means that if you get a low score back, it has been mismarked and you can get it remarked etc. Chances are it won't, and you'll get the mark you deserve. 
danhirons
 Follow
 3 followers
 14 badges
 Send a private message to danhirons
 Thread Starter
Offline14ReputationRep: Follow
 16
 20032011 14:54
(Original post by Farhan.Hanif93)
Notice how this is a disguised first order DE. Use the substitution . The use the integrating factor method to get the CF and find the particular integral by plugging in a function of the form and solving for A.
Attached working.
Is that the sort of thing you meant or have I misunderstood?
Dan 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 17
 20032011 17:35
(Original post by danhirons)
Attached working.
Is that the sort of thing you meant or have I misunderstood?
Dan
p(x) is not 1, it should be 6. Which gives you an integrating factor of exp(6x).
You then multiply through both sides of the DE by that integrating factor and note that the LHS is now d/dx[m * exp(6x)]. Follow that with integration (as you did).
Then remember that when you rearrange both sides for m, you must divide through by exp(6x) and that means that you must divide the arbitrary constant by exp(6x) too. You appear to have forgotten that.
Then use your conditions to solve for your constant and finally integrate again for y. That's your complementary function.
Your method for finding the PI looks fine but I haven't checked the working. 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 18
 20032011 22:07
(Original post by Farhan.Hanif93)
...
I thought the whole point of treating is a 1st ODE was so that, by using the substitution, you're effectively just solving 2 1st ODEs, consequently finding both the constants and the particular integral at the same time, without actually explicitly looking to find any of them.
Usually, I wouldn't post a full solution, but I think I'm just as confused as the OP was now. I like the method, so I want to use it in the future where possible:
Is it right? And if not, where did I bugger up? :/.
EDIT: I used C twice, but they're actually two different constants, so ignore that.Last edited by TwilightKnight; 20032011 at 22:11. 
Farhan.Hanif93
 Follow
 53 followers
 17 badges
 Send a private message to Farhan.Hanif93
Offline17ReputationRep: Follow
 19
 20032011 22:30
(Original post by TwilightKnight)
I think I've missed something.
I thought the whole point of treating is a 1st ODE was so that, by using the substitution, you're effectively just solving 2 1st ODEs, consequently finding both the constants and the particular integral at the same time, without actually explicitly looking to find any of them.
Usually, I wouldn't post a full solution, but I think I'm just as confused as the OP was now. I like the method, so I want to use it in the future where possible:
Is it right? And if not, where did I bugger up? :/.
EDIT: I used C twice, but they're actually two different constants, so ignore that. 
TwilightKnight
 Follow
 4 followers
 11 badges
 Send a private message to TwilightKnight
Offline11ReputationRep: Follow
 20
 20032011 22:35
(Original post by Farhan.Hanif93)
That looks fine to me. The whole point of it was that you didn't have to go through the process of dealing with a more complicated 2nd order ODE. Some could argue that it was more simple to just solve it as it was but each to their own.
Anyway, glad to see it works, I shall use it in future .
 1
 2
Reply
Submit reply
Turn on thread page Beta
TSR Support Team
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.
This forum is supported by:
 Notnek
 charco
 Mr M
 Changing Skies
 F1's Finest
 RDKGames
 davros
 Gingerbread101
 Kvothe the Arcane
 TeeEff
 The Empire Odyssey
 Protostar
 TheConfusedMedic
 nisha.sri
 claireestelle
 Doonesbury
 furryface12
 Amefish
 Lemur14
 brainzistheword
 Quirky Object
 TheAnxiousSloth
 EstelOfTheEyrie
 CoffeeAndPolitics
 Labrador99
 EmilySarah00
 thekidwhogames
 entertainmyfaith
 Eimmanuel
 Toastiekid
 CinnamonSmol
 Qer
Updated: March 21, 2011
Share this discussion:
Tweet