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    I have got no idea, anyone would help me? thank you.
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    Cauchy's Integral Formula

    If you rearrange it you have \int \frac{f(z)}{z-z_{0}} = 2\pi i f(z_{0})

    Now rearrange those formula in your questions to match the form \int \frac{f(z)}{z-z_{0}}
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    (Original post by AlphaNumeric)
    Cauchy's Integral Formula

    If you rearrange it you have \int \frac{f(z)}{z-z_{0}} = 2\pi i f(z_{0})

    Now rearrange those formula in your questions to match the form \int \frac{f(z)}{z-z_{0}}
    part 1, I got 2pi i e^(-pi i /2)
    part 2, I got - pi i

    are the answers correct?
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    Yes
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    is it not -pi.i/2 for b)?
 
 
 
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