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# Conversions (ton/year to kmol/hr) watch

1. 1. Convert 100,000 tons/year to kmol/hr

2. Convert 0.45$/gallon to$/kmol

Both questions are with regards to methanol. Molar mass = 32.04, density = 791 kg/m3

I kind of think I know what to do, but I keep getting weird results. I'll post what I've done in a sec, but can someone try it out as well and see what you get?

My working:

1.

2. Let D = $as latex wont let me use$

For some reason I don't know what to do when the $side stays. But if I take it away and add it back later then I do: Are those reasonable numbers? 2. (Original post by G A B R I E L) 1. Convert 100,000 tons/year to kmol/hr 2. Convert 0.45$/gallon to $/kmol Both questions are with regards to methanol. Molar mass = 32.04, density = 791 kg/m3 I kind of think I know what to do, but I keep getting weird results. I'll post what I've done in a sec, but can someone try it out as well and see what you get? My working: 1. 2. Let D =$ as latex wont let me use $For some reason I don't know what to do when the$ side stays. But if I take it away and add it back later then I do:

Are those reasonable numbers?
Doing it in my head so doing a bit of rounding-

(1000/32) = 31moles/kg so 31000 moles/tonne so 3.1 x 109 moles in 100000 tonnes

24 hrs in a day, 365 days/yr so 8760 hrs/yr (approx 9000)

moles/hr = 3 x 109/9 x 103 = 3.33 x x 105 so 3.33 x x 102 kmol/hr

The US gallon is about 3.8 litres (I assume it is this because the price is in US$) 3.8 litres methanol will weigh 3.04 kg (density rounded to 0.8 kg/l) 3.04 kg methanol is approx 93 moles (from above) so$ 0.45/gallon approx = $0.005/mole therefore$5/kmole

Hope this is some use
3. (Original post by Cora Lindsay)
Doing it in my head so doing a bit of rounding-

(1000/32) = 31moles/kg so 31000 moles/tonne so 3.1 x 109 moles in 100000 tonnes

24 hrs in a day, 365 days/yr so 8760 hrs/yr (approx 9000)

moles/hr = 3 x 109/9 x 103 = 3.33 x x 105 so 3.33 x x 102 kmol/hr

The US gallon is about 3.8 litres (I assume it is this because the price is in US$) 3.8 litres methanol will weigh 3.04 kg (density rounded to 0.8 kg/l) 3.04 kg methanol is approx 93 moles (from above) so$ 0.45/gallon approx = $0.005/mole therefore$5/kmole

Hope this is some use
We get the same thing for 1 and for 2 yours seems more reasonable. I got that the first time I did it, but it just thought that a kmole of something would cost more than $5. Could you help with one more thing? How would you convert 0.15$/lb in $/gallon. 791 kg/m3 = 6.6 lb/gallon so i get basically 1$/gallon
4. (Original post by G A B R I E L)
How would you convert 0.15 $/lb in$/gallon. 791 kg/m3 = 6.6 lb/gallon so i get basically 1\$/gallon

C

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