# Mathematics Applicants 2012 watch

1. (Original post by ben-smith)
Need there be?
Not really but it never hurts.
2. (Original post by Edwin Okli)
France or Belgium probably but I wouldn't mind studying a language ab initio. In fact, I would like to.
Ooh cool. That sounds good
3. (Original post by ben-smith)
What method did you use to work out that ? I didn't have a clue how to do that bit.

(Think this is probably a really stupid question ).
4. hey does anyone know any step questions that don't need C3 trig or C4 knowledge (not done it yet)
thanks
5. (Original post by anyone_can_fly)
What method did you use to work out that ? I didn't have a clue how to do that bit.

(Think this is probably a really stupid question ).
The question implies that it can be written in the form [quadratic]^2. It is also fairly obvious that the coefficients are going to be integers so right away we know that the first term is x^2 and the last is 4. We are left with one other coefficient to find, I was feeling lazy at the time so I just called it a, expanded the expression, equated coefficients to give me a=6. Some people can just factorise things like that in their heads.
6. (Original post by like_a_star)
hey does anyone know any step questions that don't need C3 trig or C4 knowledge (not done it yet)
thanks
A small goat is tethered by a rope to a fixed point at ground level on a square barn which stands in a horizontal field of grass. The sides of the barn are of length 2a and the rope is of length 4a. Let A be the area of the grass that the goat can graze. Prove that A <(or equal to) 14π(a^2) (π=pi) and determine the minimum value of A.

Here's a hint if you are struggling.

Spoiler:
Show
Think using circles!

The answer will require a diagram so I can't really type it up clearly, but if anyone wants my answer I will happily provide although it may not make much sense if you aren't thinking along the right lines.
7. (Original post by ben-smith)
The question implies that it can be written in the form [quadratic]^2. It is also fairly obvious that the coefficients are going to be integers so right away we know that the first term is x^2 and the last is 4. We are left with one other coefficient to find, I was feeling lazy at the time so I just called it a, expanded the expression, equated coefficients to give me a=6. Some people can just factorise things like that in their heads.
Oh of course, thanks
8. I'm defiantly applying to do maths finished my personal statement today . Currently thinking kings ucl royal holloway city and Kingston
9. (Original post by LoveLifeHate)
I'm defiantly applying to do maths finished my personal statement today . Currently thinking kings ucl royal holloway city and Kingston
Whom are you defying?
10. Definitely* damn iPhone spell corrections
11. (Original post by deejayy)
A small goat is tethered by a rope to a fixed point at ground level on a square barn which stands in a horizontal field of grass. The sides of the barn are of length 2a and the rope is of length 4a. Let A be the area of the grass that the goat can graze. Prove that A <(or equal to) 14π(a^2) (π=pi) and determine the minimum value of A.

Here's a hint if you are struggling.

Spoiler:
Show
Think using circles!

The answer will require a diagram so I can't really type it up clearly, but if anyone wants my answer I will happily provide although it may not make much sense if you aren't thinking along the right lines.
I've done this one, it was my first every complete solution haha
12. Gcse's: 3A*s 3As 2Bs
A levels: Maths A*(finished a year early), Further Maths, Physics, chemistry
Applying to: Cambridge, Bath, Durham, Southampton, Lancaster
Gcse's: 3A*s 3As 2Bs
A levels: Maths A*(finished a year early), Further Maths, Physics, chemistry
Applying to: Cambridge, Bath, Durham, Southampton, Lancaster
Woo Lancaster!!!!!!
Good luck!!
14. (Original post by ben-smith)
The question implies that it can be written in the form [quadratic]^2. It is also fairly obvious that the coefficients are going to be integers so right away we know that the first term is x^2 and the last is 4. We are left with one other coefficient to find, I was feeling lazy at the time so I just called it a, expanded the expression, equated coefficients to give me a=6. Some people can just factorise things like that in their heads.
That was obviously too easy

This is one of my favourites: Prove
15. (Original post by TheMagicMan)
That was obviously too easy

This is one of my favourites: Prove
Meh, bookwork. You turn it into a double integral and convert to polar coordinates. That result is too famous to ask as a brain teaser.
Beautiful result though.
16. (Original post by TheMagicMan)
That was obviously too easy

This is one of my favourites: Prove
Lol Gaussian Integral ... Brilliant question but I don't have the time now to write all that on LaTeX...
17. (Original post by LoveLifeHate)
I'm defiantly applying to do maths finished my personal statement today . Currently thinking kings ucl royal holloway city and Kingston
18. Now that I am doing Maths in University, it's surprising how many idiots manage to get in there. It's like I'm in A-level again.
19. (Original post by ben-smith)
Meh, bookwork. You turn it into a double integral and convert to polar coordinates. That result is too famous to ask as a brain teaser.
Beautiful result though.
Ok then. Prove it without any change of variable or transform.
Spoiler:
Show
Consider as well as sine reduction formulae NB: I've just realised you need to change the variable to get to sines but it's a much nicer one than polar or inverses
20. (Original post by TheMagicMan)
Ok then. Prove it without any change of variable or transform.
I'd have to be Gauss to do that

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