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# Core 4 splitting partial fractions help!! :) watch

1. the question asked me to show (2 / (x - 1) (x - 3)) in partial fractions which i did and got : (1 / (x - 3)) - (1 / (x - 1)) which is correct

it then asked to use that answer to express (4 / ((x - 3)^2)((x - 1)^2)) in partial fractions,
i thought i would just have to add a (1 / (x - 1)^2) and (1 / (x - 3)^2), which would give: (1 / (x - 3)) + (1 / (x - 3)^2) - (1 / (x - 1)) + (1 / (x - 1)^2),

but the answer in the back is very slightly different:
(1 / (x - 3)) - (1 / (x - 3)^2) + (1 / (x - 1)) + (1 / (x - 1)^2)

can someone explain why i am wrong and explain a method?
or is the book is wrong

2. anyone?
3. (Original post by goerigi)
it then asked to use that answer to express (4 / ((x - 2)^2)((x - 1)^2)) in partial fractions,
you sure that bit is correct?
4. (Original post by Freakonomics123)
you sure that bit is correct?
ohh that should be (x - 3)^2. typo! sorry
5. (Original post by Freakonomics123)
you sure that bit is correct?
so do you have any ideas
6. (4 / ((x - 3)^2)((x - 1)^2))

equals the square of

(2 / (x - 1) (x - 3)) = square of [(1 / (x - 3)) - (1 / (x - 1))]
7. (Original post by vc94)
(4 / ((x - 3)^2)((x - 1)^2))

equals the square of

(2 / (x - 1) (x - 3)) = square of [(1 / (x - 3)) - (1 / (x - 1))]
thanks but could you explain how (2 / (x - 1) (x - 3)) = square of [(1 / (x - 3)) - (1 / (x - 1))
8. (Original post by goerigi)
thanks but could you explain how (2 / (x - 1) (x - 3)) = square of [(1 / (x - 3)) - (1 / (x - 1))
the square of the square of

because;

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