x Turn on thread page Beta
 You are Here: Home

# water of crystallisation help :/ watch

1. R.A.M Anhydrous = 196.
R.A.M H20 = 18.

Grams of Anhydrous = 1.735g.

H3X ~ nH20 = 210g mol -1

Moles of H3X ~ nH20 = 0.00833 mol.

How do I work out the ratio of water molecules to H3X molecules using these?

Any help would be greatly appreciated
2. Ok, imagine you had copper sulphate.

CuSO4 : ram = 159.6

CuSO4.5H2O : ram = 159.6 + (5x18) = 249.6

So,

ram anhydrous (H3X) + n(ram H2O)=ram H3X~nH2O

196 + 18n=210

n=0.778

I guess, rounding up, you can say you have one water then. H3X.H2O

But I'd question your numbers because n should be an integer

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 22, 2011
Today on TSR

### How do I turn down a guy in a club?

What should I do?

### My dad said he's stalked me at uni!

Poll

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE