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    Any help with this question would be appreciated. Thanks

    The number of breakdowns in a manufacturing process may be assumed to follow a Poisson distribution with parameter \lamda.

    During a 30 day period it was observed that on exactly 9 days there were no breakdowns. On the remaining 21 days all that is known is that there was at least one breakdown. Find the MLE of \lamda




    (Sorry I gave up with latex couldn't get it to work...suppose, people know the probability function p(x) well though..)
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    \large P (\large X = 0)=\dfrac {e^{-\lambda}\lambda^r}{r!}


     =\frac {9}{30}

    \frac {9}{30} = e^{-\lambda}

    \ln \frac {9}{30} = {-\lambda} \ln e


    And you can find the MLE of the mean. This is just a wild guess. I think this is correct
 
 
 
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Updated: April 2, 2011
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