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# Higher Further Calculus and Stationary Point Help? watch

1. Doing a past paper, came across this question:

"A function f is defined by f(x)=(2x-1)^5

Find the coordinates of the stationary point on the graph with equation y=f(x) and determine it's nature"

So far I've differentiated f(x) to 10(2x-1)^4, then equated it to zero for Stationary Points.

Where do I go from there? How do I find the x coordinate? I know how to do stationary points normally, but not like this.
Doing a past paper, came across this question:

"A function f is defined by f(x)=(2x-1)^5

Find the coordinates of the stationary point on the graph with equation y=f(x) and determine it's nature"

So far I've differentiated f(x) to 10(2x-1)^4, then equated it to zero for Stationary Points.

Where do I go from there? How do I find the x coordinate? I know how to do stationary points normally, but not like this.
Well if and you equate that to 0, then divide through by 10 you end up with . Now what must 2x-1 be equal to if when it is raised to the power of four it is equal to zero? Remember, it's 4 identical things multipled together, and when you multiply 2 numbers together and get zero what must at least one of the numbers be equal to?
Doing a past paper, came across this question:

"A function f is defined by f(x)=(2x-1)^5

Find the coordinates of the stationary point on the graph with equation y=f(x) and determine it's nature"

So far I've differentiated f(x) to 10(2x-1)^4, then equated it to zero for Stationary Points.

Where do I go from there? How do I find the x coordinate? I know how to do stationary points normally, but not like this.
f(x)=(2x-1)^5
f'(x)=10(2x-1)^4
f'(x)=0
10(2x-1)^4=0
(2x-1)^4=0
(2x-1)=0
2x=1
x=1/2
when f'(x)>0, it is a minimum point. when f'(x)<0, it is a maximum point
In this case 1/2>0, so its nature is a minimum.
4. I now feel like a complete idiot.

Derp.

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Updated: March 22, 2011
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