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Equilibria, Energetics and Elements (F325) - June 2011 Exam. watch

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    JUNE 2010 i need help with question 7a)

    anyone 7a) june 2010
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    (Original post by potentialmedicalstudent)
    Cr2O7^2- + 14H+ + 8e- ------> 2Cr2+ + 7H20
    how did you get the 8 electrons ?
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    (Original post by azz92)
    JUNE 2010 i need help with question 7a)

    anyone 7a) june 2010
    Multiply the MnO4 one by two
    Now see if that helps..
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    Hi,

    I was wondering if others may be in the position where they feel they 'know' a sufficient amount, but are worried about this 'application' of science hinted at in the reports.

    Does anyone have any interesting predictions of how information may be woven into an 'apllication' question tommorow?

    (for instance the question on peroxide and hair in january)
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    if they asked us for a ratio of A:B
    For example, they could do this when proportioning [HA]:[A-] in a buffer system..
    Would you have to A/B.. or just leave it as A:B?
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    (Original post by hey-hey-hey)
    OK simple Qs
    Construct the equation for the oxidation of acidified iron(II) ions by oxygen..How do I start to do this?
    i get
    Fe2+ + O2 + 4H+--------> Fe3+ + 2H2O
    But the answer is this, How?
    4Fe2+ + O2 + 4H+-------------> 4Fe3+ + 2H2O

    Why the 2 in front of the Fe?
    Fe2+ ---------->Fe3+ + e-
    O2 + 4e- + 4H+ --------> 2H2O

    Then balance the e-
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    (Original post by Julian_valensi)
    Hi,

    I was wondering if others may be in the position where they feel they 'know' a sufficient amount, but are worried about this 'application' of science hinted at in the reports.

    Does anyone have any interesting predictions of how information may be woven into an 'apllication' question tommorow?

    (for instance the question on peroxide and hair in january)
    that was a stupid question and the reports basically admitted it
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    (Original post by azz92)
    how did you get the 8 electrons ?
    both sides need to have equal charges (in this case it's +4)
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    (Original post by raj16)
    wenever i ave a titration question i got through the same stages
    1. MOLES
    look for wen they give u a conc and a volume, so in this qu they give u 0.02moldm3 of KMnO4 and the volume 23.45cm3.
    Use n=cv and u shuld get 4.69x10-4 mols of KMn04

    2.Ratios
    By using the equation given u can compare the number of moles. So Mn04 2:5 H2O2.
    so divide the answer we got above by 2, thats so u get 1 mole and then times by 5. 1.1725x10-3

    1 thing to look out for in the volumes, the answer we've worked out is in 25cm3, so in 250cm3 its 10X as more, 1.1725x10-2. This is the moles of H2O2 in 250cm3.

    3.Units
    Now they want the answer in g/dm3. So i think about this in terms of units now. Where can i get grams from? mols=mass/Mr

    So 1.1725x10-2 /34= 0.39865g
    Right at the beginnin of the qu they tell u that u diluted the soultion in 25cm3.
    So we ave grams and cm3, divide cm3 by 1000 u get answer in dm3.
    25/1000=0.025DM3
    Using the units again g/dm3, i see the / meanin divide.
    FINALLY!!

    0.39865/ 0.025= 15.97g/dm3




    Really hope i didnt confuse u further

    I was stuck on this question and I get your explanation (+rep). What I don't understand is why do you do 1.1725x10-2/34= 0.39865g :confused:

    Do you mean multiply? So 1.1725 x 10-2 x 34. I think this would make more sense..
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    Guys, what equations do we need to learn?
    I know the MnO4- with Fe and the iodine thiosulphate one.
    Do we need to know any for the hydrogen fuel cell?
    Could someone list them pleaaase
    +rep
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    (Original post by Wor Carroll)
    Fe2+ ---------->Fe3+ + e-
    O2 + 4e- + 4H+ --------> 2H2O

    Then balance the e-
    Thankyou
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    When we are linking ionic size to lattice enthalpy is this sufficient

    The ionic size of ion A is smaller than ion B, this means it has a greater charge density and so the ions have a greater attraction to each other.
    This results in a more exothermic value for lattice enthalpy

    First is this sentence correct?
    Second is this sufficient if this comes up in the exam?
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    (Original post by INeedToRevise)
    Guys, what equations do we need to learn?
    I know the MnO4- with Fe and the iodine thiosulphate one.
    Do we need to know any for the hydrogen fuel cell?
    Could someone list them pleaaase
    +rep
    You need to know what happens at each electrode of the fuel cell,
    well, only of the hydrogen fuel cell.
    The overall reaction iss...
    H2 + 0.5 O2 --> H2O
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    Could somebody please explain to me how to balance this equation...

    FeO42(–) + H(+) ? Fe(3+)+ O2+ H2O

    ...to give this...

    4FeO42(–) + 20H(+) ? 4Fe(3+)+ 3O2+ 10H2O
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    (Original post by INeedToRevise)
    I was stuck on this question and I get your explanation (+rep). What I don't understand is why do you do 1.1725x10-2/34= 0.39865g :confused:

    Do you mean multiply? So 1.1725 x 10-2 x 34. I think this would make more sense..
    Woops, sorry! yh i did mean that. was typin it fast
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    (Original post by potentialmedicalstudent)
    ...
    Yep got it before you quoted me. I thought the oxidation state of cr was +8 for some reason. Thanks.
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    (Original post by INeedToRevise)
    Guys, what equations do we need to learn?
    I know the MnO4- with Fe and the iodine thiosulphate one.
    Do we need to know any for the hydrogen fuel cell?
    Could someone list them pleaaase
    +rep
    Yes you need to know the hydrogen fuel cell one they are

    1/2 O2 + H20 +2e--------> 2OH- +0.4V
    2H2O +2e- ----------> H2 + 2OH- -0.83V

    These are the half equations
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    ANYONE PLEASE! How do you work out where the equivalence line is on titration curves as Ive seen on a past paper where the line is at 33cm3 and not 25cm3
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    (Original post by CoventryCity)
    When we are linking ionic size to lattice enthalpy is this sufficient

    The ionic size of ion A is smaller than ion B, this means it has a greater charge density and so the ions have a greater attraction to each other.
    This results in a more exothermic value for lattice enthalpy

    First is this sentence correct?
    Second is this sufficient if this comes up in the exam?
    Yes more exo/neg.

    Also i doubt it would be any more than 2/3 (max) marks :/ so that should be enough imo. Maybe you could mention greater electrostatic forces of attraction and stronger ionic bonds to be more clear.
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    thanks

    this f325 exam is a confusing one it makes you feel like its easy but there are little tricks they dont show or tell you :mad:
 
 
 
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