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1. i have been struglling with a question for a while i think i have done the first half but not the second
the question is:
A ball is thrown from a point at ground level with a velocity 22ms-1 at 35degrees to the horizontal. the ground is level and horizontal and you should ignore air resistance.
a) find the horizontal and vertical components of the balls initial velocity
b) find the horizontal and vertical components of the balls acceleration

so for part a i did:
horizontal = x=Vcos(angle) i
x=22cos35 i
x=18.0 i
vertical = y=Vsin(angle) j -gt t=0
y=22sin35 -9.8x0
y=12.6 j

but for part b i wasnt sure wather to use a constant acceleration eqution or a=-gj but i use a=-gj
which gave me:
a=-9.8 x12.6j
a=-123.48
but i dont think this is right
so can anybody help me with this please thanks

Unless I'm missing something, part ii is incredibly straightforward - gravity provides a constant acceleration downwards.
3. thanks
yeah i think you are right
so in that case it would be 0i + 9.8j?
4. (Original post by millie78)
thanks
yeah i think you are right
so in that case it would be 0i + 9.8j?
I'm sure you meant 0i - 9.8j since that is what you were using previously; which is correct.
5. yes i did but thanks x

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