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    i have been struglling with a question for a while i think i have done the first half but not the second :confused:
    the question is:
    A ball is thrown from a point at ground level with a velocity 22ms-1 at 35degrees to the horizontal. the ground is level and horizontal and you should ignore air resistance.
    a) find the horizontal and vertical components of the balls initial velocity
    b) find the horizontal and vertical components of the balls acceleration

    so for part a i did:
    horizontal = x=Vcos(angle) i
    x=22cos35 i
    x=18.0 i
    vertical = y=Vsin(angle) j -gt t=0
    y=22sin35 -9.8x0
    y=12.6 j

    but for part b i wasnt sure wather to use a constant acceleration eqution or a=-gj but i use a=-gj
    which gave me:
    a=-9.8 x12.6j
    a=-123.48
    but i dont think this is right :confused:
    so can anybody help me with this please thanks
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    Agree with your answers to part i.

    Unless I'm missing something, part ii is incredibly straightforward - gravity provides a constant acceleration downwards.
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    thanks
    yeah i think you are right
    so in that case it would be 0i + 9.8j?
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    (Original post by millie78)
    thanks
    yeah i think you are right
    so in that case it would be 0i + 9.8j?
    I'm sure you meant 0i - 9.8j since that is what you were using previously; which is correct.
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    yes i did but thanks x
 
 
 
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