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    Hey, just wondered if anyone can help me with a few questions from C2 integration & differentiation.

    y=x^3-2x^2
    How do I find the point that touches the x axis?
    and
    How do I find out the shaded area?

    - I've drawn the graph out and everything; but can't seen to get to grips with it.
    Thanks
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    (Original post by iitsMee..x)
    Hey, just wondered if anyone can help me with a few questions from C2 integration & differentiation.

    y=x^3-2x^2
    How do I find the point that touches the x axis?
    and
    How do I find out the shaded area?

    - I've drawn the graph out and everything; but can't seen to get to grips with it.
    Thanks
    the point where it touches the x axis is where y = 0. You can work the equation through from there.
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    For where it touches the x-axis, y=0. So you get x^3-2x^2=0 factorise = x^2(x-2)=0, therefore crosses at (0,0) and (0,2).

    For the second part, I haven't covered that in C2 so I don't know yet, sorry.
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    i would have done it so 2x^2 = x^3, x will equal 0 for one but to find the other, then divide by x^2 get 2 = x. have you covered integration at all? if you have i can explain
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    You need to intergrate within the limits of the shaded area, if the shaded area is below the x axis you need to change the sign, if you have two shaded areas, where one is above and one is below the x axis you change the sign of the one below, then add both areas, you can get both areas by intergrating within the appropriate limits.
 
 
 
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