A discrete R.V X has probability distribution:
x -1 0 1 2 3
a b 0.1 0.3 0.2
Find the probability X is greater than E(X)
Find the values A and B.
Paul plays a game in which a fair coin is spun 4 times. If the number of heads is 0 or 1 Paul loses £5. If the number of heads is 2 Paul wins £5 and if the number of heads is 3 or 4 paul wins £10.
Show that P(W=-5) = 5/6
Thanks for your help
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- Thread Starter
- 28-03-2011 14:18
- 28-03-2011 14:26
Sum of probabilities is always one...gives an equation for a and b.
Use the formula for E(X) to form another equation for a and b.