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    (Original post by magicalelf)
    What did people get for the bond angle?
    i forgot to do this bit. ah well only 1 mrk
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    (Original post by lou12)
    this equation gave a complex with 2- right? please say yes!
    Yes, C204 are 2-, and 2 of them, so 4- then the Cu is 2+, so overall complex was 2- (if I got it right hah)
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    (Original post by lou12)
    this equation gave a complex with 2- right? please say yes!
    It would be 2- yes
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    (Original post by magicalelf)
    What did people get for the bond angle?
    I think i put 120 degrees because it's the same case with ethene (trigonal planar shape).
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    how many marks will i lose if i didnt divide the 2 moles to make it 1 mole.
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    (Original post by jimmy303)
    I said that cell X was a standard cell since the emf didn't change (a high resistance voltmeter prevents the reaction from going so the equilibrium isn't approached and emf stays the same) but I was strongly tempted to put a hydrogen fuel cell...

    Thought it was cheeky of them to ask for the reaction when the lead cell is recharged!

    And only one colour of complex ions question :mad:

    Other than those qualms I think it was ok.

    edit: I also thought it was a tad cheeky of them to give us the reaction for the formation of 2 moles of ammonia then asked us to do questions based on the formation of one mole :eek:
    oh crap i didnt realise this wil i get error carries forward marks
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    (Original post by magicalelf)
    What did people get for the bond angle?
    I put 90, wasn't too sure though
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    what were the two shapes that the palladium complex could have and the coordination number?
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    (Original post by subsist)
    Hey did people divide the ammonia equation by 2 cause it asked for one mole?
    I did but my final answer was 454. I think that's way off. I don't know what I did wrong in the calculations. I added up the enthalpies of all bonds broken then added up enthalpies of all bonds formed then found the difference. What did I miss? :confused:
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    After reading people's answers. I'm pretty sure I've flopped now
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    (Original post by jimmy303)
    I think i put 120 degrees because it's the same case with ethene (trigonal planar shape).
    why trigonal planer because theres 6 co-ordinate bonds?

    i put octaheldral shape, and bond angle 90 degrees, wasnt sure on the 90 tho, i thought the two c2o42- ions would form a square planer shape around the cu, with h20 above and below. but then im not sure if the bond angle changes due to them both being negative and repelling... hmm
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    (Original post by Zakir)
    what were the two shapes that the palladium complex could have and the coordination number?
    It had four ligands so tetrahedral or square planar i think.
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    what was oxidation state of pladdium
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    (Original post by jimmy303)
    It had four ligands so tetrahedral or square planar i think.
    yh thats what i put..

    what about the coordination number when it was with S02?
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    (Original post by Zakir)
    what were the two shapes that the palladium complex could have and the coordination number?
    i got tetrahedral and octahedral total guess tho haha
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    (Original post by Zakir)
    yh thats what i put..

    what about the coordination number when it was with S02?
    +2
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    (Original post by Zakir)
    yh thats what i put..

    what about the coordination number when it was with S02?
    so42- is -2, and ammonia neutral, so +2?
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    **** didn't divide ammonia by 2 so I got -199.How many marks would I lose.
    Did anyone get 298.3 K for the temperature and any less that that would not make it feasible.
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    (Original post by cleo101)
    what was oxidation state of pladdium
    +2 I think is what i got. Not 100% if that's the answer
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    (Original post by magicalelf)
    why trigonal planer because theres 6 co-ordinate bonds?

    i put octaheldral shape, and bond angle 90 degrees, wasnt sure on the 90 tho, i thought the two c2o42- ions would form a square planer shape around the cu, with h20 above and below. but then im not sure if the bond angle changes due to them both being negative and repelling... hmm
    Octahedral shape yes and the C2O4(2-) form a square planar without the two waters yes because it said the waters were opposite each other.

    120 degrees because http://en.wikipedia.org/wiki/Oxalate the carbons are bonded to three things then its trigonal planar, so unless i misread the question (i thought it wanted the bond angle between carbon and the oxygen) then i think it's 120 degrees.

    If it asked for bond angles of the coordinate bonds with the metal ion then I'm wrong :P
 
 
 
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