a bead, of mass m, is threaded on a smooth circular loop of wire of radius a and which is fixed in a vertical plan. The bead is released from rest at the end of a horizontal diamter. Find the reaction of the wire when the bead has turned through an angle x
the furthest I can get is that NR - mgsin(x) = (mv^2)/a
I don't know how to get the acceleration in terms of x
never mind, got it
mechanics 2 help Watch
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Last edited by Misiak; 28-03-2011 at 22:53.
- 28-03-2011 22:32