x Turn on thread page Beta
 You are Here: Home >< Maths

# Cartesian equation of a curve from parametric equations. watch

1. Curve is defined by x= 3sint, y= 2cost

Show that the cartesian equation of the curve is 4x^2+9y^2 = 36

How do I show it? Do I substitute the values and show that LHS=RHS?
2. Or you could obtain the cartesian curve by using the fact that sin^2 + cos^2 =1.
3. (Original post by gunmetalpanda)
Curve is defined by x= 3sint, y= 2cost

Show that the cartesian equation of the curve is 4x^2+9y^2 = 36

How do I show it? Do I substitute the values and show that LHS=RHS?

make it so you have just sin(t) and cos(t) e.g. x/3 = sin(t)

then use the trig identity sin^2x + cos^2x = 1

Just say if I haven't explained that very well and i'll try again.

TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: March 30, 2011
Today on TSR

### I've studied the wrong subject

...Should I go back to school?

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams