The Student Room Group

URGENT!!

could someone please please solve and show me how to find the general solution of the following 2nd order differential equation.

y''+3y'+2y=(e^x)+(e^-x)

Thanks in advance :biggrin:
Reply 1
What do you already know about solving 2nd order linear ODEs? This is no different to any other. The only snag is in choosing a particular integral, in which case substituting y=Aex+Bxexy= Ae^x + Bxe^{-x} and solving comparing coefficients to find A,B does the trick (note the x after the B, because x=1x=-1 is a root of the characteristic polynomial and exe^{-x} is in the forcing term).
(edited 13 years ago)

Quick Reply

Latest