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    I am stuck on part 3 of this question.

    1) A curve is given by the parametric equations: x=t^2 and y+1/t
    find dy/dx in terms of t

    (answer is -1/2t^3)

    2) Show that the equation of the tangent at the point P (4, -1/2) is

    x-16y=12

    3) Find the value of the parameter at the point where the tangent meets the curve again.

    (im having trouble in finding the equation of the curve which the markscheme said is : x^3 - 24x^2 +144x+256=0 )

    thanks for the help
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    Start off by writing y in terms of x only (so eliminate t) for the equation of the curve.

    Then just substitute x = 12 + 16y (equation of the tangent) into the equation of the curve and solve the resulting equation. Hence find t using the original parametric equations of the curve.
 
 
 
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Updated: March 31, 2011
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