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What are the structural isomers for the following alkenes? watch

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    What are the structural isomers for the following alkenes?

    Butene
    Pentene
    Hexene
    Heptene
    Octene
    Nonene
    Decene


    Thanks.
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    How are we meant to tell you? Do you want us to explain how to do them? Do you want us to draw all of the different ones for each alkene? Just google it, there will be loads of websites.
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    I'd guess N/2 where N= even no of carbons in straight hydrocarbon

    (N-1)/2 where N= odd no of hydrocarbons
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    (Original post by Bloodbath)
    I'd guess N/2 where N= even no of carbons in straight hydrocarbon

    (N-1)/2 where N= odd no of hydrocarbons
    Unfortunately there are still no algorithms that generate the correct number of isomers, even using the most powerful computational devices.

    The search for one is actually a bit of a chemistry/computing Holy Grail...

    Take a look at this paper:

    http://www.scctm.org/Awards/Ballard_Paper.pdf
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    (Original post by charco)
    Unfortunately there are still no algorithms that generate the correct number of isomers, even using the most powerful computational devices.

    The search for one is actually a bit of a chemistry/computing Holy Grail...

    Take a look at this paper:

    http://www.scctm.org/Awards/Ballard_Paper.pdf
    that's really interesting. Never knew that
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    (Original post by charco)
    Unfortunately there are still no algorithms that generate the correct number of isomers, even using the most powerful computational devices.

    The search for one is actually a bit of a chemistry/computing Holy Grail...

    Take a look at this paper:

    http://www.scctm.org/Awards/Ballard_Paper.pdf
    guess I forgot about the branched ones. All he has to do is draw out all the different branched isomers and count the number of ways he can arrange the double bonds for each branched isomer (not counting any duplicates caused by symmetry)
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    (Original post by Bloodbath)
    guess I forgot about the branched ones. All he has to do is draw out all the different branched isomers and count the number of ways he can arrange the double bonds for each branched isomer (not counting any duplicates caused by symmetry)
    You do realise that there are 75 isomers of decane! :eek:

    With decene, including geometrics and optical isomers, there must be huge number.
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    (Original post by charco)
    Unfortunately there are still no algorithms that generate the correct number of isomers, even using the most powerful computational devices.

    The search for one is actually a bit of a chemistry/computing Holy Grail...

    Take a look at this paper:

    http://www.scctm.org/Awards/Ballard_Paper.pdf
    Interesting
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    Thanks for your replies.
 
 
 
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