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# Done the arrhenius equation right? watch

1. I've
• Done four reactions at different temperatures
• calcualted the inital rate of reaction at each temperature
• substituted this into the rate equation to calcualte the rate constant
• plotted a graph of 1/T against ln(rate constant)
• Drawn a straight line of best fit and calculated the gradient
• Put the gradient equal to -Ea/R
• Converted Ea from J to KJ
2. (Original post by misfit1993)
I've
• Done four reactions at different temperatures
• calcualted the inital rate of reaction at each temperature
• substituted this into the rate equation to calcualte the rate constant
• plotted a graph of 1/T against ln(rate constant)
• Drawn a straight line of best fit and calculated the gradient
• Put the gradient equal to -Ea/R
• Converted Ea from J to KJ
i think you meant you plotted ln(rate constant) against 1/T
Arrhenius eqn is k = Aexp(-E/RT)
so ln k = ln(A) - (E/R)(1/T)
y = mx + c

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