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    (Original post by david2457)
    What is the operator and how does it work?


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    the operator is a product of the numbers
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    (Original post by david2457)
    What is the operator and how does it work?
    It's a product. Same as a summation, except you multiply each value together instead of adding.
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    (Original post by Lutski)
    It's a product. Same as a summation, except you multiply each value together instead of adding.
    It can't be as simple as multiplying all the numbers together?


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    Weirdly found roentgenium easier than silver and gold...found Henry Mosely totally by accident on a random google image serach...
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    can someone give me some help on Rg. I found out who it is, but have absolutely no idea what to do.
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    Okay, for Gold the value on wikipedia for the mass is wrong, it's too low by 50g. Hope this helps to people.
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    which values do you multiply together?
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    (Original post by david2457)
    It can't be as simple as multiplying all the numbers together?
    Pretty much.
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    (Original post by Lutski)
    Pretty much.
    But I'm not getting the right answer


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    is it just mass/proton number Moseley anomalies because I can only see 3 of them

    I'm really puzzled by the sequence
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    in gold, he wants the time in seconds, thats it?
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    (Original post by lpdsr)
    in gold, he wants the time in seconds, thats it?
    In days...
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    Anyone got anything for Rg? I'm pretty much stuck.
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    yeh me too, I don't know what x1 x2 x3 etc are..
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    Can someone please message me a clue for Rg
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    (Original post by ChemistryPartner)
    Can someone please message me a clue for Rg
    and me!
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    which symbol is this in Rg?
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    ?
    (Original post by Llewellyn)
    In days...
    =D
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    well I've given up. I'm exhausted and now wish I'd spent a good deal of the last few hours sleeping

    maybe next year?
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    (Original post by ChemistryPartner)
    Can someone please message me a clue for Rg
    (Original post by ChemistryPro)
    and me!
    ditto (need to sleep, so any help would be very much appreciated)
 
 
 
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