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    Write an equation, including state symbols, to represent the average C-H bond enthalpy on methane, CH4.

    I literally don't have a clue what to do.
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    C-H (g) ----> C (g) + H(g)
    then next to it, write delta H = whatever amount you're given for it in kJ mol.
    I've got +413 for it!
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    that's just for one C-H bond btw, seeing as there are 4 you may have to balance it? orrr maybe 4 C-H ----> C (g) + 2H2 (g) .. whatever looks right from what you've learnt :|
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    (Original post by almxo)
    that's just for one C-H bond btw, seeing as there are 4 you may have to balance it? orrr maybe 4 C-H ----> C (g) + 2H2 (g) .. whatever looks right from what you've learnt :|
    If you are working out the average bond enthalpy for methane then it's:

    1/4CH4(g) ---> 1/4C(g) + H(g)

    Or put it another way one quarter the enthalpy change for:

    CH4(g) ---> C(g) + 4H(g)
 
 
 
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