# AQA BIOL1 Biology Unit 1 Exam - 16th May 2011 watch

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1. (Original post by Sparkly-Star)
Oh no I meant 4.c.iii) and 5.b) too not the ones I mentioned lol. I know how to do those.
For 4Ciii, the question asks, starting with glucose + fructose, so you know that when those two combine there will be one h2o molecule released (makes sucrose).
Then it says R, where a fatty acid is attached to a lipid, we know that when glycerol+3fatty acids attach, condensation occurs, and a h2o molecule is released. So you've just gotta know that when two of those combine, h20 comes out. There are 8 Rs + 1 h2o from glucose + fructose = 9.
2. (Original post by Sparkly-Star)
Oh no I meant 4.c.iii) and 5.b) too not the ones I mentioned lol. I know how to do those.
Whilst we wait for help, can you please explain 3d ii to me? Looked at MS but still confuses me :P Thanks
3. I HOPE THERE IS NOTHING ON CHOLERA/ SODIUM POTASSIUM PUMP!!! I will actually get 0 on an applied Cholera question :L oh, I hope there are not as many mathsy questions...I always mess up somewhere :/
I hope there is lots on immunity though
4. The January 2011 paper was actually awful
5. (Original post by liviaaa)
It's 9. Look at the diagram above, count how many R groups there are 8, and plus the X bond. 9

--

20cm3 = 1 mol

So

4cm3 = 0.2 mol (divide it by 5)

As there is 4cm3 of NaCl, there must be 16cm3 of water, to make it up ot 20 cm3.
You're awesome!
6. Aaaaah since alot of you are thinking immunity will come up tomorrow, im gonna go revise that section in detail again now. Then i think i'll do the final practice paper that i havnt done yet....
7. Ooooh can someone please explain how you convert UM measurements into MM? i really dont get that atall. xD I always get it wrong. :/
8. (Original post by Tericon)
Whilst we wait for help, can you please explain 3d ii to me? Looked at MS but still confuses me :P Thanks
This one is quite simple. You know that the equation is:

Cardiac output = stroke volume x heart rate

They told us that the guy's heart rate became lower but the cardiac output is still the same. This means that his stroke volume must've gone up to still get the same cardiac output, so this means more blood is pumped out of the heart per heartbeat. And the reason it pumps more blood could be due to an increase in the strength of the heart muscle.
9. (Original post by Abby :))
Ooooh can someone please explain how you convert UM measurements into MM? i really dont get that atall. xD I always get it wrong. :/
essentially, 1mm=1x10^3 um and 1mm=1x10^6 nm

So you would measure it in mm and then do either x10^3 or x10^6 of it depending if it asks for um or nm
and divide by the magnification.
Simples
10. Why are controls used in experiments??
11. (Original post by reaperguy)
essentially, 1mm=1x10^3 um and 1mm=1x10^6 nm

So you would measure it in mm and then do either x10^3 or x10^6 of it depending if it asks for um or nm
and divide by the magnification.
Simples
Thank you so much! <3 You just explained it better then the textbook hahaha.
12. (Original post by BeejTheone)
Why are controls used in experiments??
To prove that the effect is due to the addition of something e.g. a chemical e.g. in an enzyme experiment the control is almost always boiled enzyme to show that the change is always due to the enzyme and nothing else.

In terms of a control group you would always use a placebo and keep everything else the same

You must make sure you say both those things to get both the marks
13. (Original post by Sparkly-Star)
This one is quite simple. You know that the equation is:

Cardiac output = stroke volume x heart rate

They told us that the guy's heart rate became lower but the cardiac output is still the same. This means that his stroke volume must've gone up to still get the same cardiac output, so this means more blood is pumped out of the heart per heartbeat. And the reason it pumps more blood could be due to an increase in the strength of the heart muscle.
Thank you, makes perfect sense now
14. (Original post by liviaaa)
It's 9. Look at the diagram above, count how many R groups there are 8, and plus the X bond. 9

--

20cm3 = 1 mol

So

4cm3 = 0.2 mol (divide it by 5)

As there is 4cm3 of NaCl, there must be 16cm3 of water, to make it up ot 20 cm3.

Cheers, that mol stuff was really confusing me
15. (Original post by reaperguy)
To prove that the effect is due to the addition of something e.g. a chemical e.g. in an enzyme experiment the control is almost always boiled enzyme to show that the change is always due to the enzyme and nothing else.

In terms of a control group you would always use a placebo and keep everything else the same

You must make sure you say both those things to get both the marks
Cheers mate
16. (Original post by Sparkly-Star)
You're awesome!

(Original post by A_clizzy)
Cheers, that mol stuff was really confusing me
It's okay
17. Is facilitated diffusion; Movement of water soluble molecules from an area of high concentration to an area of lower concentration with use of proteins? No ATP required..?
18. (Original post by BeejTheone)
Is facilitated diffusion; Movement of water soluble molecules from an area of high concentration to an area of lower concentration with use of proteins? No ATP required..?
Lol edit: I read your post wrong. Yeah it is with the use of specific shaped channel proteins.
19. What if they ask us about the role in temperature and ph and substrate concentration as the 5markers? you never know...
20. enzymes are always the most easy part of bio unit 1 and considering most of that was asked in the EMPA Paper i dont think it will. OFC there will be at least 1 enzyme question but it will prolly be on inhibitors.

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