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    If I have the following reaction:

    2Mg(s) + O2 -----> 2MgO(s)


    I need the following number of grams to react with 48g and 12g of magnesium:

    48g Mg -----> 32g O2

    12g Mg -----> 8g O2

    Is that right?

    Thanks.
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    (Original post by SWEngineer)
    If I have the following reaction:

    2Mg(s) + O2 -----> 2MgO(s)


    I need the following number of grams to react with 48g and 12g of magnesium:

    48g Mg -----> 32g O2

    12g Mg -----> 8g O2

    Is that right?

    Thanks.
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    (Original post by charco)
    Thanks a lot.
 
 
 
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