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1. Solve lnx=6/(5-lnx)

I know the answer is e^2 or e^3 but I don't know how to get there. Any hints?
2. Multiply the equation by 5-lnx and you will have a quadratic in lnx.
3. 5ln^2x-lnx=6 ?
I tried solving that with no luck, I'll go over my working again though
4. Oh, basic factorising mistake, thanks

5. Let y = ln x

Now I get neg rep for helping out ?
6. (Original post by sdgvrgverg)
5ln^2x-lnx=6 ?
I tried solving that with no luck, I'll go over my working again though
Nope, it should be ln^2x - 5lnx + 6 = 0, then you could take lnx = y and you'll have y^2 - 5y + 6 = 0 which you could then factorise to give (y-2)(y-3) therefore the solutions are y = 3 and y = 2 which means lnx = 2 and lnx = 3 as y = lnx, then you do:

lnx = 2
x = e^2

lnx = 3
x = e^3

=D

Let y = ln x

Now I get neg rep for helping out ?
Because you're not supposed to give him the full solution.

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