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# Need help.. watch

1. Hello, im trying to prove a point to somenoe, in this equation what oxidises/reduces?

Sn+HNO3-------> SnO2 + NO2 + H2O

Hydrogen does right?
2. (Original post by jamesrune75)
Hello, im trying to prove a point to somenoe, in this equation what oxidises/reduces?

Sn+HNO3-------> SnO2 + NO2 + H2O

Hydrogen does right?
Tin is oxidised, nitrogen is reduced
3. (Original post by Plato's Trousers)
Tin is oxidised, nitrogen is reduced
What bout hydrogen? that changes from

Sn+HNO3-------> SnO2 + NO2 + H2O

+1 to +2
4. (Original post by jamesrune75)
What bout hydrogen? that changes from

Sn+HNO3-------> SnO2 + NO2 + H2O

+1 to +2
nope. H stays at +1
5. (Original post by Plato's Trousers)
nope. H stays at +1
Sn+HNO3-------> SnO2 + NO2 + H2O

Theres H2O on the right hand side, so it shud be 1x2=2 right?
6. (Original post by jamesrune75)
Sn+HNO3-------> SnO2 + NO2 + H2O

Theres H2O on the right hand side, so it shud be 1x2=2 right?
in H2O you have oxygen at -2 and two hydrogens at +1
7. (Original post by Plato's Trousers)
in H2O you have oxygen at -2 and two hydrogens at +1
So we dont count each individual hydrogen? Just the one?
8. (Original post by jamesrune75)
So we dont count each individual hydrogen? Just the one?
eh?

compounds have overall oxidation state zero. So, in water, the two hydrogens must balance the one oxygen.

2(+1) + (-2) = 0

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