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    When we add a reducing sugar to a Fehling's solution, we expect for example to see a red-orange precipitate. Why is that?

    Thanks.
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    (Original post by SWEngineer)
    When we add a reducing sugar to a Fehling's solution, we expect for example to see a red-orange precipitate. Why is that?

    Thanks.
    Reducing sugars contain the aldehyde group.

    This is another reduction reaction (read the Tollens post again) only this time the Copper(II) ions are getting reduced to Cu(I)

    The copper(I) appears as red insoluble copper(I) oxide
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    (Original post by charco)
    Reducing sugars contain the aldehyde group.

    This is another reduction reaction (read the Tollens post again) only this time the Copper(II) ions are getting reduced to Cu(I)

    The copper(I) appears as red insoluble copper(I) oxide
    Thanks for your reply.
 
 
 
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