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# AEA June 2011 watch

1. (Original post by Agent Fiasco)
i think u must be right cause
how did u do it??

i expanded it than intergrated them each than put the limits i must have messed up some values
I can't remember the question as I spent ages worrying about Q6... I just remember my answer :P
2. Loooool who did the 1 mark vector Q on finding A lies on the line and didn't do the rest?
3. (Original post by Agent Fiasco)
thats wat i did fbut for my T parameter i had a huge value somefin like 141/50 so i gave up on it

btw u know the next few question on vectors was one of them prove that angle APB is 90????
Yeah you're to use dot product, to prove , as cos90=0. But then you got to find B first which depends on the P' from (a). That is the only method I can think of.
4. What were people's P' Vector? Mine was
5. (Original post by Ultimate1)
Loooool who did the 1 mark vector Q on finding A lies on the line and didn't do the rest?
haha I did that! that made my happy :P
6. (Original post by implus)
What were people's P' Vector? Mine was
Did you find t by getting the perpundicular distance from P to the line right? What did you get T as??
7. (Original post by implus)
What were people's P' Vector? Mine was
I didn't get this. If you manage to prove (c) correctly with this value of P', then your P' is correct.
8. (Original post by superkinetic)
Yeah you're to use dot product, to prove , as cos90=0. But then you got to find B first which depends on the P' from (a). That is the only method I can think of.
I managed to work out B as B was on line l right? so i made the point b as eqaution with T and then solved it for and worked out B would that be correct?
9. (Original post by Ultimate1)
Did you find t by getting the perpundicular distance from P to the line right? What did you get T as??
I think it was

My vector for which lied on the line L and such at PX was perpendicular to the line L was
10. (Original post by implus)
I think it was

My vector for which lied on the line L and such at PX was perpendicular to the line L was
WTF I got 158/69. Did you do like p.x =0 right? Arghhh I was on the right track but was getting weird number for t
11. (Original post by Agent Fiasco)
I managed to work out B as B was on line l right? so i made the point b as eqaution with T and then solved it for and worked out B would that be correct?
But you are to find position vector B before concluding that , not using to work out position vector B. I dunno if the examiners will allow you to work out position vector B by using facts from subsequent parts of the qn.

(Original post by Ultimate1)
WTF I got 158/69. Did you do like p.x =0 right? Arghhh I was on the right track but was getting weird number for t
I think it's pure carelessness. I got 50t=175 which leads to t=7/2. But I think I am careless enough not to calculate P' properly.
12. but didnt they tell us that APB was 90 degrees or did they ask to prove i fink i read the question wrong
13. (Original post by Agent Fiasco)
but didnt they tell us that APB was 90 degrees or did they ask to prove i fink i read the question wrong
If I didn't recall wrongly, the qn ask you to find position vector B before proving the angle is 90 degrees.
14. (Original post by Ultimate1)
Loooool who did the 1 mark vector Q on finding A lies on the line and didn't do the rest?
Yayyy yayy me too
I'm so happy someone is accompanying me
15. Weren't the equation to find t something like -7(-13-5t) + 2(3-3t) + 7(something) = 0
16. So what are the chances of any of you getting the grade that you want. I think it's probably 0 for me, which sucks.
17. (Original post by Raimu)
So what are the chances of any of you getting the grade that you want. I think it's probably 0 for me, which sucks.

I think I didn't do well enough either to get the merit I need. The paper was very hard, when I did the past papers I usually got around 53 marks but this one I will be lucky to get 40
18. Just scanned through the posts but didn't see it: did anyone do Q1? I was convinced that was a typo. Oh and I'll be lucky if I got a merit with what I answered >.<

Also are you guys still waiting on the paper? I can scan one in at 6:00 tonight if no ones done it before then.

Apologies if either of the above have already been posted; just scanned through the recent posts quickly on my way out the door.
Just scanned through the posts but didn't see it: did anyone do Q1? I was convinced that was a typo. Oh and I'll be lucky if I got a merit with what I answered >.<

Also are you guys still waiting on the paper? I can scan one in at 6:00 tonight if no ones done it before then.

Apologies if either of the above have already been posted; just scanned through the recent posts quickly on my way out the door.

This is what implus posted...

(Original post by implus)
This is how I did question 1:

$let \ \theta +35^{\circ} = A \\ and \ let \ \theta -53^{\circ} = B \\tanA=CotB \\ \frac{SinA}{CosA}=\frac{CosB}{SinB} \\ SinASinB=CosACosB \\ CosACosB-SinASinB=0 \\ Cos(A+B)=0 \\ Cos(2\theta -18^{\circ})=0 \\ 2\theta -18^{\circ}= 90^{\circ}, 270^{\circ} \\ \theta = 54^{\circ},144^{\circ}$
20. I took pictures of the paper and uploading on mediafire now... don't really know how to reduce the size so I'll send a link in 10 minutes

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