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# AEA June 2011 watch

1. anyone get t=-1 for the last part of the last question?
2. someone help me with mediafire! I've never used it before... I uploaded the paper but can't find a download link to send to you?
3. (Original post by lcw)
anyone get t=-1 for the last part of the last question?
I got this value too.
4. You'll just have to download them 1 by 1 for now....sorry

http://www.mediafire.com/?0gsp8jx8l0mapmp
http://www.mediafire.com/?be16w5k82lj55fc
http://www.mediafire.com/?43i7d34k1z779lf
http://www.mediafire.com/?1368bkz5wkndnsz
http://www.mediafire.com/?7aazlkd9y69g9yw
http://www.mediafire.com/?mkhhmkfy3wttwrc

Enjoy!
5. (Original post by soczek322)
someone help me with mediafire! I've never used it before... I uploaded the paper but can't find a download link to send to you?
go to mediafire.com click on my files at top

click on the files u uploaded and copy paste the url
6. Anyone help on the first part of Vector Q?
7. (Original post by Ultimate1)
Anyone help on the first part of Vector Q?
I found a vector perpendicular to line via dot product,
then set up a line in form r=a +Xb with a =p and b=perpendicular
I then found value of X up to intersection, doubled it and subbed it back in to find P', anyone agree with this
8. (Original post by arob752)
I found a vector perpendicular to line via dot product,
then set up a line in form r=a +Xb with a =p and b=perpendicular
I then found value of X up to intersection, doubled it and subbed it back in to find P', anyone agree with this
yep
9. (Original post by implus)
This is how I did question 1:

$let \ \theta +35^{\circ} = A \\ and \ let \ \theta -53^{\circ} = B \\tanA=CotB \\ \frac{SinA}{CosA}=\frac{CosB}{SinB} \\ SinASinB=CosACosB \\ CosACosB-SinASinB=0 \\ Cos(A+B)=0 \\ Cos(2\theta -18^{\circ})=0 \\ 2\theta -18^{\circ}= 90^{\circ}, 270^{\circ} \\ \theta = 54^{\circ},144^{\circ}$
fffffffffffffff

That's so simple. I hate exams. I only made one substitution (x=theta+35) and got my answers in terms of tan35 and tan53.
10. Did anyone get 4 for 3c?
11. (Original post by Pheylan)
Did anyone get 4 for 3c?
I got 3root3 / 8 ?
12. Just realised that the second term by itself is bigger than 4. Wtf was I thinking
13. (Original post by Pheylan)
Just realised that the second term by itself is bigger than 4. Wtf was I thinking
Area = sinx * (cosx)^3

That cannot be bigger than 1...
14. (Original post by soczek322)
Area = sinx * (cosx)^3

That cannot be bigger than 1...
Question 3c, I wrote 4
15. FML I just realised I wrote down 2^4 = 8
16. Answer to 3(c) is 70, surely? (k = 6, p = 4/3, q= 3/5, let n go to infinity). (I assume this is the sum question - question numbers are missing in the 1st uploaded page).
17. (Original post by Pheylan)
Question 3c, I wrote 4
Oh sorry I think I got 70 but wasn't really sure - I subbed in p = 4/3 and q = 3/5 and k = 6 into part b)
18. I wrote S/6 = <stuff>, then multiplied by 6 at the end - thought it'd give the same answer
19. (Original post by Pheylan)
I wrote S/6 = <stuff>, then multiplied by 6 at the end - thought it'd give the same answer
It does, assuming you don't make any mistakes.
20. I probably mixed up p and q or something. ****ing idiot

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