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    Integrate

    1) 9t sint dt

    which I think is -9t cost + 9 sint + c

    2) 12 sin^2t cost dt

    which I think is -6 cos^2t + c

    Please advise
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    Agree with the first one.

    For the second, the best thing to try is the substitution u=sint, from which the solution flows quite nicely.
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    How do you sub in u for sin2t?
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    How do you sub in u=sint for sin2t?
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    (Original post by bradz1993)
    How do you sub in u=sint for sin2t?
    You would probably have to change the sin2t to 2sintcost.

    There's no direct way of subbing it in.

    Got a question in mind?

    EDIT: Or do you mean sin^2t? Which is what your question 2 says atm. In which case its just u^2.
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    if it is power two, then let sub u=cosx so that makes
    integrate 12 (sin t)^2 d(sint)
 
 
 
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