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# PHYA1 - Physics Unit 1 Exam - 24th May 2011 watch

• View Poll Results: Are you resitting this unit?
YES!
45.30%
NO!
54.70%

1. (Original post by Limitless)
How do you know people never found it interesting you do not have to reply to the comment to acknowledge it. Science is not just about learning to pass exams. It is about learning and trying to understand the world around you.
Yup, you can shut up now.
2. for the terminal pd as it decrese and curent increase , i reffered to the equations V=W/Q and I=Q/t
3. (Original post by buzza786)
for the terminal pd as it decrese and curent increase , i reffered to the equations V=W/Q and I=Q/t
That should probably be fine
4. (Original post by Naum)
Yup, you can shut up now.
Couldn't think of a proper comeback eh! Oh well...
5. (Original post by Naum)
That should probably be fine
woohhhoo. atleast ive gt a mark
6. Unofficial mark scheme anyone. Seriously need to nail Mechanics!!!
7. (Original post by ciarangc)
Unofficial mark scheme anyone. Seriously need to nail Mechanics!!!
Same. I've got a weeks revision time for mechanics so I'm not too fussed.
8. im such an idiot man , when it sed calucltae r , i didnt know it was the gradient , i did it the long way , E= IR+Ir, i could have saved soo much time
9. (Original post by Limitless)
Couldn't think of a proper comeback eh! Oh well...
What do you mean comeback lol? I'm not here to have a verbal war with you or anything, calm down.
10. I really think the mark boundries will be quite low. Does anyone thing ill get any marks for this. This is for the calculating the internal resistance "So for some reason i used 1.5 as the emf (1 mark lost) and again for some reason i calculated the lost volts as :1.5v-1.4V = 0.1V. I then read this value off the graph and I got A Current value of 0.3. R=V/I so R=0.1/0.3 so i got an answer around 0.33 ohms, will i get anything?
11. (Original post by TimetoSucceed)
what was the gradient for on the graph? =/ i probably fukd up big time
I'm almost definite it was 0.45 ohms.

12. (Original post by Limitless)
Depends on the grade I get in August. If it is a B I'm requesting a remark. I asked for my paper back for the Jan11 paper there are like 6 marks the examiner never gave me and with those 6 I could have moved from a C to an A. I can't get a remark for that paper now I'm well pissed off.
This.

In jan i got my paper back, about 5 marks marked very very harshly, but by then you cant get it remarked.

They should be more carefully moderated, especially when theres four marks between whole grades.
13. I knoiw, you are right. But will i get anything for my answer??
14. For the charge/mass ratio... I did

2 x 1.60x10^-19 (electron charge)/ 4 x 1.67x10-27 (mass of nucleons)

which gave me 4.8x10^7, I think.
15. fuk my life, effort and no reward, whats the point?
16. (Original post by tuckaa)
This.

In jan i got my paper back, about 5 marks marked very very harshly, but by then you cant get it remarked.

They should be more carefully moderated, especially when theres four marks between whole grades.
I know. There shouldn't be a need to remark. They should just mark it properly the first time. Then we have to pay for the remark ourselves yes you may get refunded if you go up a grade in that paper but what if you go up by a few marks and your overall grade increases. You have to pay for the remark and get no refund.

(Original post by Naum)
What do you mean comeback lol? I'm not here to have a verbal war with you or anything, calm down.
So calling me a dumbass was just friendly talk?
17. when you retake in jan when do you get your results? and you can't remark?
18. I really think the mark boundries will be quite low. Does anyone thing ill get any marks for this. This is for the calculating the internal resistance "So for some reason i used 1.5 as the emf (1 mark lost) and again for some reason i calculated the lost volts as :1.5v-1.4V = 0.1V. I then read this value off the graph and I got A Current value of 0.3. R=V/I so R=0.1/0.3 so i got an answer around 0.33 ohms, will i get anything?
19. I am mixed now. I have got what some of Y'all are saying, just made silly mistakes.

I PRAY the grade bounaries are low.

20. (Original post by Brasileira)
For the charge/mass ratio... I did

2 x 1.60x10^-19 (electron charge)/ 4 x 1.67x10-27 (mass of nucleons)

which gave me 4.8x10^7, I think.
Think I got this too.

I think I may have lost a mark on the one about terminal p.d., didn't explain it very well.

Also, on the question on the back about calculating the energy dissipated per second (or whatever it was), what did everyone get? Was I right to calculate power, P = I^2r, using the internal resistance r?

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