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PHYA1 - Physics Unit 1 Exam - 24th May 2011 watch

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    (Original post by Dizzy in my Head)
    Yeah, I got the top equation, too, because there wasn't any neutrino to conserve the pion-ness.

    And I put weak interaction, because I just did. Because I'm stupid like that. Anyone got a definite answer to that?
    erm i put the same as you. But i believe it was teh second due to lepton number needing to be conserved. Because it was an antineutrino (-1) and a muon*+ (also -1) so it wasnt possible
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    (Original post by Lucy149)
    i dont think we have mentioned the one in the first question yet about whether particle X was a lepton baryony or meson
    i put baryon but i wouldnt count on any of my answers
    It was a baryon

    A proton was formed, which is a baryon
    To conserve baryon number, X had to be a baryon
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    what did you put for the difference between the special particles?
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    Am i the only one that got 3.3A for the 2nd to last one? I did 10/3. I used 10v because over a parallel combo, the voltage on each side is equal to the max voltage; and on that specific side there was only one component so all of the voltage was passing through it. no? :confused:

    Also i got 5v for the last one because if the resistance in the two resistors is the same - THe current will also be the same. And as there are two components, the total Voltage through one resistor is the max V/2. (10/2 = 5)
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    (Original post by Dizzy in my Head)
    What do you mean wrong, they got that right!

    It asked for two baryons, one of which is a neutron (though you needed to state two - but you still got one mark if you didn't).
    They won't get the mark for that. It wasn't specific to the question. You had to mention both bayrons in context, just checked with my Physics teacher.
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    (Original post by Lucy149)
    i dont think we have mentioned the one in the first question yet about whether particle X was a lepton baryony or meson
    i put baryon but i wouldnt count on any of my answers
    I got baryon, too, as the baryon number would not be conserved if it wasn't.
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    What was the argon question? Was the proton number +1 more and the nucleon number the same?
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    (Original post by Spas_13)
    They won't get the mark for that. It wasn't specific to the question. You had to mention both bayrons in context, just checked with my Physics teacher.
    Yeah, I'm sorry - I was skim reading and thought they had put neutron. But you can't dent the confidence of people in telling them they'll have to re-sit, it's bad enough finding the question they thought was right is wrong!
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    (Original post by jackegan93)
    What was the argon question? Was the proton number +1 more and the nucleon number the same?
    No, it was +1 for the proton number, and the same for nucleon number - as it wasn't beta minus decay, it was beta plus decay...
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    Bro you just said what I said.. and Ok fair enough can't remember the question
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    Can somebody answer my question please? It's up this page about the last two question.
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    (Original post by LewisS911)
    Am i the only one that got 3.3A for the 2nd to last one? I did 10/3. I used 10v because over a parallel combo, the voltage on each side is equal to the max voltage; and on that specific side there was only one component so all of the voltage was passing through it. no? :confused:

    Also i got 5v for the last one because if the resistance in the two resistors is the same - THe current will also be the same. And as there are two components, the total Voltage through one resistor is the max V/2. (10/2 = 5)
    That parallel combo was only exposed to a voltage of 4v, as it was in series with the other resistor Z
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    Can someone answer my question as well please - it's on the previous page. Thanks
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    (Original post by LewisS911)
    Can somebody answer my question please? It's up this page about the last two question.
    yeahh i think your right i did get the answer but for some reason i divided the 3.3A by the root 2? dont know why

    imk just really confused right now the paper was horendous!
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    (Original post by Dizzy in my Head)
    Yeah, I'm sorry - I was skim reading and thought they had put neutron. But you can't dent the confidence of people in telling them they'll have to re-sit, it's bad enough finding the question they thought was right is wrong!
    Yo mate, just found out that you were correct, I was wrong. It turns out both answers are valid.
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    Can anyone remember the question about the Argon atom, like what it actually said?
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    Well anyway the top equation didn't conserve strangeness. And strangeness is conserved in strong interactions. So the top one can't work.
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    (Original post by TooEasy123)
    Well anyway the top equation didn't conserve strangeness. And strangeness is conserved in strong interactions. So the top one can't work.
    That's actually what I said.. will I still get marks?
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    (Original post by jackegan93)
    That's actually what I said.. will I still get marks?
    TBH i doubt it and I gave this as an answer. Its only 2 marks tbh, u can drop like 7 and get 100% =D
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    (Original post by TooEasy123)
    Well anyway the top equation didn't conserve strangeness. And strangeness is conserved in strong interactions. So the top one can't work.
    The top equation underwent Weak Force interaction, AFAIK. The quark flavour changes, so the top one looked valid. The second one had unbalanced lepton numbers.
 
 
 
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