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PHYA1 - Physics Unit 1 Exam - 24th May 2011 watch

  • View Poll Results: Are you resitting this unit?
    YES!
    45.30%
    NO!
    54.70%

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    I calculated my internal resistance to be 0.448 ohms I left my answer to 3 significant figures, do you think i could get full marks for this?
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    (Original post by maths134)
    this is assuming a lot... did u get 40 ums out of 60 ? or raw marks because arnt empas/isas out of 50 raw marks. Anyway if it is ums, then 40/70 will probably be a C (jan conversion) which was 70umns. So thats 110. You would need 130 which is not possible. So no A. Btw this is quite easy to do via AQA ums converter, next time do it yourself.
    where is the ums convertor?

    and is it really out of 50? in that case maybe maybe 35/50 =/
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    Q: Nuclear force = The strong nuclear force has very short range ranging from 1-3fm outside this range the electromagnetic force is > than the strong nuclear force
    Q: Specific charge = 4.79x10^7CKg^-1
    Q: internal resistance = 0.448 ohms
    Q: Last question pd = 2V
    Q: current question on last page 1.3A
    Q: Most stable baryon = proton
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    (Original post by Tyrone-C)
    Q: Nuclear force = The strong nuclear force has very short range ranging from 1-3fm outside this range the electromagnetic force is > than the strong nuclear force
    Q: Specific charge = 4.79x10^7CKg^-1
    Q: internal resistance = 0.448 ohms
    Q: Last question pd = 2V
    Q: current question on last page 1.3A
    Q: Most stable baryon = proton
    can you remember the question at the end of the emf graph, answer was with units Watts. ?
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    (Original post by Tyrone-C)
    Q: Nuclear force = The strong nuclear force has very short range ranging from 1-3fm outside this range the electromagnetic force is > than the strong nuclear force
    Q: Specific charge = 4.79x10^7CKg^-1
    Q: internal resistance = 0.448 ohms
    Q: Last question pd = 2V
    Q: current question on last page 1.3A
    Q: Most stable baryon = proton
    I got 0.67 A and 4V for the last two, do you think ill get atleast 1 mark ? :/
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    I cant remember what I put but i know I used the equation P=I^2R
    I think i did P = (0.89)^2 x (0.448->internal resistance) = 0.35W
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    (Original post by maths134)
    can you remember the question at the end of the emf graph, answer was with units Watts. ?
    The unit was already there wasnt it?
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    (Original post by Tyrone-C)
    I cant remember what I put but i know I used the equation P=I^2R
    I think i did P = (0.89)^2 x (0.448->internal resistance) = 0.35W
    I got the same
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    May get a mark for recognising that the ratio of amps was 1/3 and/or 2/3, what you did was right but the wrong way round maybee one mark

    The second one you might get 1 mark for saying that the resistors in parrallel have 4V, but not sure either.
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    The EMPA is 20% of the final grade right?

    If I get

    35/50 for the EMPA [marks]
    80 UMS for Unit 1
    and 120 UMS for Unit 2

    Do I still have the chance of scraping a low A or would I be stuck with a B and have to resit an exam? Sorry for asking a lot of questions btw.
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    (Original post by Msd27)
    The unit was already there wasnt it?
    yeh i just want to know what everyone got for the answer lol
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    (Original post by TimetoSucceed)
    The EMPA is 20% of the final grade right?

    If I get

    35/50 for the EMPA [marks]
    80 UMS for Unit 1
    and 120 UMS for Unit 2

    Do I still have the chance of scraping a low A or would I be stuck with a B and have to resit an exam? Sorry for asking a lot of questions btw.
    isa are marked harshly because of how people do. So 35/50 could be a D/best a C. So its likely to be around 42 ums, if u do get 80 ums and then 120 then its an A. But its looking unlikely because 80 ums seems optimistic for ur raw score.
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    (Original post by Tyrone-C)
    I calculated my internal resistance to be 0.448 ohms I left my answer to 3 significant figures, do you think i could get full marks for this?
    why wouldn't you get full marks for that?
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    (Original post by maths134)
    yeh i just want to know what everyone got for the answer lol
    haha sorry just worrying that it said "stating an appropiate unit!"
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    (Original post by Msd27)
    haha sorry just worrying that it said "stating an appropiate unit!"
    what did u get for it btw ? numerically
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    PLEASE some 1 tell me if i would get a mark for putting 0.67 A and 4V for the last two questions!!!!!!PLEASEEE
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    What did u guys get 4 da question about y a neutrino is used instead of an antineutrino... so confuzled...
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    hey what did everyone get for the specif charge question i was so baffled
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    (Original post by maths134)
    what did u get for it btw ? numerically
    erm 0.3w? i think it may have had a few more digits but that roughly
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    (Original post by Smilie 101)
    What did u guys get 4 da question about y a neutrino is used instead of an antineutrino... so confuzled...
    Okay so lepton number has to be conserved in the interaction.... lepton number on right hand side = 0 therefor the lepton number on righthand side has to also equal 0 therefor as a positron is emmited that has a lepton number -1 therefor the other particle has to have lepton number +1 therefor electron neutrino not anti electron neutrino
 
 
 
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