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# Stuck on an additional maths Q watch

its part (b) i dont get
my attempt is shown but it seems wrong
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2. CCF03042011_00000.pdf (417.4 KB, 73 views)
3. first thing, ha that looks rude!

second:

pi*x^2+2yx-8=0

pi*x^2+10x-pi*x^2-2x^2-8=0 (sub in y=x)

2x^2-10x+8=0

... pretty easy from there :P
4. Agree with you as far as

The value you are substituting in for y however is not correct. You've used the value from part (a)(iii) which is the value for y for the maximum area. You want the value for y in terms of x, from part (a)(i)

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Updated: April 3, 2011
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