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# Help maths questions watch

1. Hi I'm struggling with this questions. any help appreciated.
At time t seconds its distance s metres from a fixed point is given by:
s = t^3 - 12t^2 + 45t + 10
1) find velocity in terms of t
2) find acceleration in terms of t
3) find two values of t which is stationary.
4)Find value of t when acceleration is zero.
2. Well and , so for (1) and (2) it's just a case of differentiating. For (3) the question doesn't make much sense -- find the values of t for which what is stationary? Take the 'what' here and differentiate it to find the corresponding t-values. For (4) you need to solve the equation for t.
3. I take it that this refers to some body, whose distance at time t is given by said formula, and that q3 refers to the 2 values of t for which said body is stationary. In that case, same as nuodai pointed out for q4, just solve v(t)=0 for t. As the function v(t) is quadratic, you'll get 2 sollutions.
4. Thanks for the help just to make sure I understand it .
1) t =3v^2 - 24 +45
2)t =6a

4)t = 6 x 0
Still unsure on question 3 though
5. (Original post by aaron007)
Thanks for the help just to make sure I understand it .
1) t =3v^2 - 24 +45
2)t =6a

4)t = 6 x 0
Still unsure on question 3 though
1) v=3t^2 -24t +45
2) a=6t -24
3) stationary body means solve v=0
4) solve a=0

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