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    Assume that we have this alcohol: (CH3)3COH. In this case, we will have three methyl functional groups on the only C.

    Now, and I know that the formula may be wrong, but just want to ask if we see a formula like the following, on which C will the CH3 be located, the first C (from the left), or the second one?

    CH(CH3)3COH

    Thanks.
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    (Original post by SWEngineer)
    Assume that we have this alcohol: (CH3)3COH. In this case, we will have three methyl functional groups on the only C.

    Now, and I know that the formula may be wrong, but just want to ask if we see a formula like the following, on which C will the CH3 be located, the first C (from the left), or the second one?

    CH(CH3)3COH

    Thanks.
    That's an impossible compund. You have a Texas carbon! Try drawing it, and you'll see
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    (Original post by Plato's Trousers)
    That's an impossible compund. You have a Texas carbon! Try drawing it, and you'll see
    The first carbon from the lefyt, right?
 
 
 
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