f(x,y) = x^2 + xy/3, 0<x<1, 0<y<2
I have to find Pr(y<x)
As its a bivariate i know ill have to integrate f(x,y)dxdy, but what do I do with the limits of x and y?
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Bivariate PDFs watch
- Thread Starter
- 04-04-2011 17:10
- 04-04-2011 17:57
Bit rusty on this...but here goes.
Consider the rectangular region 0<x<1, 0<y<2. Shade the part for which y<x.
Can you evaluate the double integral over this region?